3 years ago

How many valence electrons does a fluorine atom contain? a. 2 b. 5 c. 7 d. 9

Chemistry

1 answer:

juin [17]3 years ago

6 0

F---atomic number 9---1s2 2s2 2p5 -----7 electrons

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Ksenya-84 [330]

Answer:

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What would be the best way to measure the volume of a small ?

WITCHER [35]

You can use a graduated cylinder.

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A 7.36 g sample of copper is contaminated with a additional 0.51 g sample of zinc. suppose an atomic mass measurement was perfor

liubo4ka [24]

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3 years ago

A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.

Alenkinab [10]

Answer:

$\Delta V = 234.736\,mL$

Explanation:

The quantity of moles of ethanol in the solution is:

$n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)$

$n_{C_{2}H_{5}OH} = 4.985\,mol$

The mass and volume of ethanol in the solution are, respectively:

$m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)$

$m_{C_{2}H_{5}OH} = 229.658\,g$

$V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }$

$V_{C_{2}H_{5}OH} = 290.964\,mL$

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

$\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)$

$\Delta V = 234.736\,mL$

8 0

3 years ago

What volume of 1.75 M hydrochloric acid (HCl aq) must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid?

Airida [17]

Answer:

$V_1=0.0714L$

Explanation:

Hello there!

In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:

$n_1=n_2$

And in terms of volume and concentration:

$C_1V_1=C_2V_2$

Thus, we can solve for the volume of the concentrated HCl as shown below:

$V_1=\frac{C_2V_2}{C_1}$

Therefore, we plug in the data to get:

$V_1=\frac{0.250M*0.500L}{1.75 M}\\\\V_1=0.0714L$

Best regards!

7 0

3 years ago