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Butoxors [25]
3 years ago
8

What volume of 1.75 M hydrochloric acid (HCl aq) must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid?

Chemistry
1 answer:
Airida [17]3 years ago
7 0

Answer:

V_1=0.0714L

Explanation:

Hello there!

In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:

n_1=n_2

And in terms of volume and concentration:

C_1V_1=C_2V_2

Thus, we can solve for the volume of the concentrated HCl as shown below:

V_1=\frac{C_2V_2}{C_1}

Therefore, we plug in the data to get:

V_1=\frac{0.250M*0.500L}{1.75 M}\\\\V_1=0.0714L

Best regards!

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<h3>What is balanced equation?</h3>

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brainly.com/question/26694427

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Read 2 more answers
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