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svetoff [14.1K]
4 years ago
7

Factor 11x(x-2)+3(x-2)

Mathematics
2 answers:
Tems11 [23]4 years ago
5 0

Answer:

11x^2-19x-6

Step-by-step explanation:

distribute 11x into (x-2) and 3 into (x-2)

11x^{2}-22x+3x-6

combine like terms

-22x+3x=-19x

thats all... it can't go any further

11^2-19x-6

hope this helps

Stells [14]4 years ago
4 0

Answer:

(11x+3)(x-2)

Step-by-step explanation:

11x2-22x+3x-6

11x-19x-6

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Sidana [21]

Answer:

f(x)=8500\sin\left(\frac{\pi}{6}\left(x-1\right)\right)+33500

Step-by-step explanation:

Given information:

Maximum revenue = 42000

Minimum revenue = $25000

Time period = 12 months

We need to write a function that models the boutique's revenue during the year, where corresponds to the month.

f(x)=Asin(B[x-C])+D           .... (1)

where, A is amplitude, \frac{2\pi}{B} is period, C is phase shift and D is midline.

A=Amplitude =\frac{Maximum-Minimum}{2}\Rightarrow \frac{42000-25000}{2}=8500

D=midline =\frac{Maximum+Minimum}{2}\Rightarrow \frac{42000+25000}{2}=33500

Period=\frac{2\pi}{B}

12=\frac{2\pi}{B}\Rightarrow B=\frac{\pi}{6}

Substitute the value of A, B and D in equation (1).

f(x)=8500\sin\left(\frac{\pi}{6}\left(x-C\right)\right)+33500         ..... (2)

In April, revenue of the store is $42000. So, the graph passes through the point (4,42000).

42000=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)+33500

42000-33500=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)

8500=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)

Divide both sides by 8500.

1=\sin\left(\frac{\pi}{6}\left(4-C\right)\right)

\sin \frac{\pi}{2}=\sin\left(\frac{\pi}{6}\left(4-C\right)\right)

On comparing both sides we get

\frac{\pi}{2}=\frac{\pi}{6}(4-C)

3=4-C

C=4-3

C=1

Substitute the value of C in equation (2).

Therefore, the required function is f(x)=8500\sin\left(\frac{\pi}{6}\left(x-1\right)\right)+33500.

5 0
3 years ago
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