Using the Pythagorean theorem a^2 + b^2 = c^2
where a and b are the legs and c is the hypotenuse
so a = 6 and c = 8
lets solve for b
6^2 + b^2 = 8^2
36 + b^2 = 64
b^2 = 64 - 36
b^2 = 28
b = sqrt(28)
b = 5.29
b = 5.3 yards
The correct answer for the question that is being presented above is this one: "<span>The missing digit is 3."</span>
The missing digit is represented by A ⇒ $1A2, where A represents a whole number from 0 to 9.
Try substituting any number from 0 to 9 for A (the middle digit or tens place) , then divide by 11 members.
<span>Option 2: A = 3 ⇒ $1 </span><span>3 </span>2
$ 132 ÷ 11 = $12
The only one-digit that gives a whole number quotient when it takes the place of tens digit in $1 __2 is<span> 3.</span><span> Because $ 132 ÷ 11 = $ 12. (Option 2)</span>
The missing digit is 3.
Hello.
-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h
Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.
-7h - 8h + 10 > -4h + 11
Add like terms.
-15h + 10 > -4h + 11
Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.
Subtract 10 from both sides. Then, add 4h to both sides.
-15h + 4h > 11 - 10
Simplify.
-h > 1
Divide both sides by -1.
However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <
-h ÷ -1 < 1 ÷ -1
h < -1
The answer is definately A
Answer:12
Step-by-step explanation:
