a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
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Answer: 5 cos x
<u>Step-by-step explanation:</u>
y = sin x is y = cos x shifted to the right π/2 units.
y = 5 sin (x + π/2) is a shift to the left π/2 units (which results in cos x) and . an amplitude of 5.
--> y = 5 cos x
Answer:
1/12
Step-by-step explanation:
Probability of an even number
3/6 = 1/2
Probability of one showing up
1/6
Probably of even number on first try and 1 on second try
1/2 * 1/6 = 1/12
For this case we have that by definition, the point-slope equation of a line is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points:

We found the slope:

Thus, the equation is of the form:

We substitute one of the points and find "b":

Finally, the equation is:

Answer:

2-2=0
5-3=2
so the answer is o over 2 aka 0/2