A^2 + b^2 = c^2....where a and b are the legs, c is the hypotenuse
3^2 + b^2 = 7^2
9 + b^2 = 49
b^2 = 49 - 9
b^2 = 40.....take sqrt of both sides, eliminating the ^2
b = square root of 40 <==
For the answer to the question above,
<span>a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
c) Now use a = v² / r
where a was found above
and r was given
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given </span>
Answer:
Step-by-step explanation:
I got (x+4) (x-2)
I feel like its wrong. Sorry i tried
The answer is C. 64 teachers.
14 x 64= 896
so 1 x 64= 64
