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Genrish500 [490]
3 years ago
5

How many grams in 82 moles of CO2

Chemistry
1 answer:
Tems11 [23]3 years ago
6 0

44.0 g/mol

hope it helps

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What is atoms in your own words
san4es73 [151]

Atom is the smallest indivisible particle of matter.

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3 years ago
Calculate the following:
Brrunno [24]

Follow these steps to solve the given equation:

Multiply the two decimal figures together and find the sum of the exponents, that is,

(1.5 * 1.89) * 10 ^4+3

(2.835) * 10^7

10^7 can also be written as e.70

'e' stands for exponential. 

Therefore, we have  2. 835 e 7.0 = 2.8 e 7.0.

Based on the calculations above, the correct option is A. 

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3 years ago
When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

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3 years ago
Balance this equation: CH4 +2O2--------&gt; ___ CO2 + ___ H2O
Lubov Fominskaja [6]

Answer:

b-1 CO2+ 2H2O

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How are oxidation-reduction reactions related to how you use energy?
Tems11 [23]

Answer:

In oxidation reduction reactions, one species gets reduced by taking on electron(s) and another species gets oxidized by losing electrons. They also flow by a wire

Explanation:

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