In the figure we have three parallel lines cut by two transversals
The theorem stares:
If two or more parallel lines are cut by two transversals, then they divide the transversals proportionally.
Applying this theorem we have:
To solve for x we cross multiply
6x=20
Dividing both sides by 6 we have:
The second option x=
is the right answer
Answer:
6p
Step-by-step explanation:
9p - 3p needs to have the like terms combined. 9 - 3 is 6, and since you have to keep the p, the answer is 6p.
Answer:
72 degrees
Step-by-step explanation:
To determine the value of DBC, we first have to determine the value of q
Angle on a straight line = 180 degrees
7q - 46 + 3q + 6 = 180
10q - 40 = 180
collect like terms
10q = 180 + 40
10q = 220
q = 22
Substitute for q in angle dbc
3(22) + 6 = 72 degrees
The characteristic equation for this ODE is
which has roots at
, so the general solution is
Given
, we have
and
, we have (upon differentiating
)
So the particular solution is
Answer:
y = m x + b equation for a straight line
m m' = -1 for perpendicular lines
Thus m' = -1/2 is required
Check:
-1/2 * -6 + 2 = = 3 + 2 = 5 = y for the last equation give
