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Dima020 [189]
3 years ago
11

Please help me! study island

Mathematics
1 answer:
ANEK [815]3 years ago
3 0

Answer:

B. 5/6

Step-by-step explanation:

\frac{1}{3} ÷ \frac{2}{5} = 0.83333333

0.83333333 ≈ \frac{5}{6}

Hope this helps :)

You might be interested in
How to solve -6<-2x<14
algol13
Hey there! :) 

-6 < -2x < 14

We're trying to solve for x. To solve for x, we must isolate x.

So, let's divide everything by -2!

-6 ÷ -2 < -2x ÷ -2 < 14 ÷ -2

**Remember : when dividing by a negative number, you MUST switch the sign! So, if the sign is ">" then we switch it to "<" and the other way around **

3 > x > -7

So, our answer is : → 3 > x > -7

~Hope I helped!~
4 0
3 years ago
In the right triangle above a=2.7 and b=4.3. Find the value of c, rounded to the nearest tenth
morpeh [17]

Answer:

  5.1

Step-by-step explanation:

Since there is no diagram provided here, we assume that c is the length of the hypotenuse, so we have ...

  c² = a² +b² . . . . . . Pythagorean theorem

  c² = 2.7² +4.3² = 25.78

  c = √25.78 ≈ 5.0774

  c ≈ 5.1

7 0
4 years ago
Solve the equation 1/6(x - 5) = 1/2(x + 6)
Semmy [17]

Answer:

-23/2

Step-by-step explanation:

x-5=3(x+6)

x-3x=18+5

-2x=23

x=-23/2

5 0
3 years ago
Subract (8x+6)-(x+4)
NeX [460]

Step-by-step explanation:

8x + 6) - (x + 4)

8x + 6 - (x + 4)

8x + 6 - x - 4

7x + 2

4 0
3 years ago
A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that
inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, H_0 : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, H_1 : p \neq 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

                T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } } ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

            \hat p = percentage of readers who own a particular make of car in a

                  sample of 220 = 0.30

            n = sample size = 220

So, Test statistics = \frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }

                             = -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

3 0
3 years ago
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