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yanalaym [24]
2 years ago
6

The sum of the prime numbers between 40 and 50

Mathematics
2 answers:
vodka [1.7K]2 years ago
7 0

Answer:

The answer is

<h2> 131</h2>

Step-by-step explanation:

prime numbers between 40 and 50 are

41 , 43, 47

Their sum is

41 + 43 + 47

<h3>= 131</h3>

Hope this helps you

kramer2 years ago
4 0

Answer:

Step-by-step explanation:

Prime numbers are numbers that only have two divisors of 1 and itself.

PRIME NUMBERS INCLUDED BETWEEN 40 AND 50 =

41.43.47.

41 + 43 + 47 = 131

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If j= 14, find the value of 1/2j.
Yakvenalex [24]

Answer:7

Step-by-step explanation:

1/2 of j is the same as j ÷ 2

14 ÷ 2 = 7

8 0
2 years ago
Consider the function p(t) shown, state the intervals on which the function is increasing.
satela [25.4K]

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its A

Step-by-step explanation:

because A is a reasonable explanation

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2 years ago
Read 2 more answers
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;16\text{ }^5/_6

\text{Equation:}\\&#10;16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Start with the integers.}\\&#10;16+3=19\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{...then with the fractions, but rewrite them first to make it easier.}\\&#10;^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add the integer and fraction together.}\\&#10;25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
2 years ago
2. How these concepts are used indifferent situations?​
Neko [114]
If you tell me the concepts you’re referring to I might be able to help
8 0
2 years ago
Find the value of x,
Gekata [30.6K]

Answer: x = -7

Concept:

From the given graph, we can see that it is an isosceles triangle since the two base angles are congruent.

In geometry, an isosceles triangle is a triangle that has two sides of equal length.

If you are still confused, you may refer to the attachment below for a graphical explanation or tell me.

Solve:

<u>Given information</u>

First Side = 7

Second Side = x + 14

<u>Given expression deducted from the definition of an isosceles triangle</u>

Second Side = First Side

<u>Substitute values into the expression</u>

x + 14 = 7

<u>Subtract 14 on both sides</u>

x + 14 - 14 = 7 - 14

\boxed{x=-7}

Hope this helps!! :)

Please let me know if you have any questions

5 0
2 years ago
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