Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))
Let A = arcsin(-5/13) = -arcsin(5/13)
Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12
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Answer:
X1=-4+4i
X2=-4-4i
Step-by-step explanation:
X^2+8x+32=0
Δ=b^2-4ac=8^2-4(32)=-64<0
X1=(-b-i√Δ) /2a=(-8-8i)/2=-4-4i
X2=(-b+i√Δ) /2a=(-8+8i)/2=-4+4i
First set up a proportion because they are similar triangles:
9/3x-20 = (72+9)/(56+3x-20)
9/3x-20 = 81/3x+36
9(3x+36) = 81(3x-20)
27x+324 = 243x-1620
1944 = 216x
x = 9
Answer:
0.9 or .9
Step-by-step explanation:
9 out 10 are shaded
In percentage, 90%
In fraction 9/10
So we could plot those points, 0, 5. When x is 0, y is 5. When x is 6, y is 0. I think if wrong sorry
