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3 years ago

Find the value of x. A) 71 B) 72 C) 73 D) 75

Mathematics

2 answers:

natita [175]3 years ago

3 0

146° + (-39 +x)° = 180°

Subtract 146° on both sides.

(-39 +x)° = 180° - 146°

(-39 +x)° = 34°

(x - 39)° = 34°

Add 39° on both sides

x = 34° + 39°

x = 73°

Your final answer is C) 73.

nataly862011 [7]3 years ago

3 0

146 - 39 + x = 180

107 + x = 180

x = 73

Your answer is C) 73.

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Naya [18.7K]

Answer:

The answer is 1 3/8 (B)

Step-by-step explanation:

3 1/4 - 1 7/8 = 1 3/8

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2 years ago

How do I find the vertex and the standard form? Plz explain

xenn [34]

Answer:

Vertex form

y = -4(x + 3)^2 + 10

Standard form;

y = -4x^2-24x - 26

Step-by-step explanation:

Mathematically, we have the vertex form as

y = a(x-h)^2 + k

(h,k) represents the vertex

We have h as -3 and k as 10

y = a(x+3)^2 + 10

To get a, we substitute any of the points

Let us use (-1,-6)

-6 = a(-1+3)^2 + 10

-6-10 = 4a

4a = -16

a = -16/4

a = -4

So we have the equation as;

y = -4(x+3)^2 + 10

For the standard form;

We expand the vertex form;

y = -4(x + 3)(x + 3) + 10

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7 0

3 years ago

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

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4 years ago

If gumballs cost 150 a bag ,and there 15!gumballs in each bag much do you need to charge for each gumball in order to make money

pshichka [43]

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3 years ago

Read 2 more answers

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maxonik [38]

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Answer:

Step-by-step explanation:

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wins + losses = 40

w + (w-18) = 40

2w = 58

w = 29

The Rangers won 29 games.

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3 years ago