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Luda [366]
3 years ago
7

How do I find the vertex and the standard form? Plz explain

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

Vertex form

y = -4(x + 3)^2 + 10

Standard form;

y = -4x^2-24x - 26

Step-by-step explanation:

Mathematically, we have the vertex form as

y = a(x-h)^2 + k

(h,k) represents the vertex

We have h as -3 and k as 10

y = a(x+3)^2 + 10

To get a, we substitute any of the points

Let us use (-1,-6)

-6 = a(-1+3)^2 + 10

-6-10 = 4a

4a = -16

a = -16/4

a = -4

So we have the equation as;

y = -4(x+3)^2 + 10

For the standard form;

We expand the vertex form;

y = -4(x + 3)(x + 3) + 10

y = -4(x^2 + 6x + 9) + 10

y = -4x^2 - 24x -36 + 10

y = -4x^2 -24x -26

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 1

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<u>Step 2: Find g(1)</u>

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  2. Multiply:                               g(1) = 3 - 2
  3. Subtract:                              g(1) = 1

<u>Step 3: Find f[g(1)]</u>

  1. Substitute in g(1):                    f[g(1)] = 2(1) + 1
  2. Multiply:                                   f[g(1)] = 2 + 1
  3. Add:                                         f[g(1)] = 3
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