Answer:
(a) The mean time to fail is 9491.22 hours
The standard deviation time to fail is 9491.22 hours
(b) 0.5905
(c) 3.915 × 10⁻¹²
(d) 2.63 × 10⁻⁵
Explanation:
(a) We put time to fail = t
∴ For an exponential distribution, we have f(t) =
Where we have a failure rate = 10% for 1000 hours, we have(based on online resource);
e^(1000·λ) - 0.1·e^(1000·λ) = 1
0.9·e^(1000·λ) = 1
1000·λ = ㏑(1/0.9)
λ = 1.054 × 10⁻⁴
Hence the mean time to fail, E = 1/λ = 1/(1.054 × 10⁻⁴) = 9491.22 hours
The standard deviation = √(1/λ)² = √(1/(1.054 × 10⁻⁴)²)) = 9491.22 hours
b) Here we have to integrate from 5000 to ∞ as follows;
(c) The Poisson distribution is presented as follows;
p(x = 3) = 3.915 × 10⁻¹²
d) Where at least 2 components fail in one half hour, then 1 component is expected to fail in 15 minutes or 1/4 hours
The Cumulative Distribution Function is given as follows;
p( t ≤ 1/4) .
Answer:
Vehicle Dynamics for use with MATLAB/Simulink (VDMS) is a lumped-parameter, 15 degrees-of-freedom vehicle simulation program that reads input files containing chassis, suspension kinematics and compliances, tire, driveline, and aerodynamic inputs.
Explanation:
hope it helps you
Answer:
Q = 62 MJ
Explanation:
given data
ideal gas mixture He = 3 kmol
ideal gas mixture Ar = 7 kmol
temperature t1 = 27°C = 300 K
pressure p1 = 200 kPa
solution
we apply here charle's law for pressure p constant that is
v ∝ T ..................1
and put here value we get
\frac{2v1}{v1} = \frac{t2}{300}
solve it we get
t2 = 600 K
so here mass of He is
mass = mole of He × molecular weight He
mass = 3 × 4
mass = 12 u
and
mass of Ar is
mass = mole of Ar × molecular weight Ar
mass = 7 × 40
mass = 280
and
heat supply will be
heat supply = mHe × CpHe × ΔT + mAr × CpAr × ΔT ................2
and here we use gas table and we get
CpHe = 5.19 (kJ/(kg K)) and CpAr = 0.5203 (kJ/(kg K))
put here value and we get
Q = 12 × 5.19 × 10³ (600-300) + 280 × 0.5203 × 10³ ( 600 -300 )
Q = 62 MJ
Answer:
The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.
Explanation:
The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.