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2 years ago

The operating sequence to light the main burners on an intermittent pilot system is:______.

Engineering

1 answer:

11111nata11111 [884]2 years ago

7 0

The pilot valve and spark igniter are energized, the pilot flame is proved, and then the main gas valve is energized.

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An engineer must design a rectangular box that has a volume of 9 m3 and that has a bottom whose length is twice its width. What

Jet001 [13]

Answer:

$Length =3$ $Height = 2$ and $Width = \frac{3}{2}$

Explanation:

Given

$Volume = 9m^3$

Represent the height as h, the length as l and the width as w.

From the question:

$Length = 2 * Width$

$l = 2w$

Volume of a box is calculated as:

$V = l*w*h$

This gives:

$V = 2w *w*h$

$V = 2w^2h$

Substitute 9 for V

$9 = 2w^2h$

Make h the subject:

$h = \frac{9}{2w^2}$

The surface area is calculated as:

$A = 2(lw + lh + hw)$

Recall that: $l = 2w$

$A = 2(2w*w + 2w*h + hw)$

$A = 2(2w^2 + 2wh + hw)$

$A = 2(2w^2 + 3wh)$

$A = 4w^2 + 6wh$

Recall that: $h = \frac{9}{2w^2}$

So:

$A = 4w^2 + 6w * \frac{9}{2w^2}$

$A = 4w^2 + 6* \frac{9}{2w}$

$A = 4w^2 + \frac{6* 9}{2w}$

$A = 4w^2 + \frac{3* 9}{w}$

$A = 4w^2 + \frac{27}{w}$

To minimize the surface area, we have to differentiate with respect to w

$A' = 8w - 27w^{-2}$

Set A' to 0

$0 = 8w - 27w^{-2}$

Add $27w^{-2}$ to both sides

$27w^{-2} = 8w$

Multiply both sides by $w^2$

$27w^{-2}*w^2 = 8w*w^2$

$27 = 8w^3$

Make $w^3$ the subject

$w^3 = \frac{27}{8}$

Solve for w

$w = \sqrt[3]{\frac{27}{8}}$

$w = \frac{3}{2}$

Recall that : $h = \frac{9}{2w^2}$ and $l = 2w$

$h = \frac{9}{2 * \frac{3}{2}^2}$

$h = \frac{9}{2 * \frac{9}{4}}$

$h = \frac{9}{\frac{9}{2}}$

$h = 9/\frac{9}{2}$

$h = 9*\frac{2}{9}$

$h= 2$

$l = 2w$

$l = 2 * \frac{3}{2}$

$l = 3$

Hence, the dimension that minimizes the surface area is:

$Length =3$ $Height = 2$ and $Width = \frac{3}{2}$

6 0

3 years ago

Rearrange the formula to make “u” the subject. <br><br> v - u<br> ——— = t<br> a

solong [7]

Answer:

u = v - a * t

Explanation:

v - u

t = ------

v - u = a * t

v - a * t = u

therefore, u = v - a * t

5 0

3 years ago

The occupants of a remote village rely exclusively on a single micro hydro facility for all of their electricity needs. The hydr

nordsb [41]

Answer:

In summer the power available is 357.55 kW and in winter the power available is 59.59 kW

Explanation:

Given data:

height = 1500 ft = 457.2 m

30 gallon = 0.114 m³

5 gallon = 0.019 m³

In summer the power available is:

$P=\mu \rho ghQ$

Where

μ = efficiency = 0.7

ρ = density of water = 1000 kg/m³

g = gravity = 9.8 m/s²

Q = 0.114 m³

Replacing:

$P=0.7*1000*9.8*457.2*0.114=3.575x10^{5} W=357.55kW$

In winter the power available is

$P=0.7*1000*9.8*457.2*0.019=59591.45W=59.59kW$

6 0

3 years ago

How has dissection used in engineering?

NeTakaya

Answer:

Product dissection has been widely deployed in engineering education as a means to aid in student's understanding of functional product elements, development of new concept ideas, and their preparation for industry.

Explanation:

I hope this helps :) have a wonderful day!

6 0

3 years ago

Read 2 more answers

The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that deliv

Nataliya [291]

The question is incomplete. The complete question is :

The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2590 hp and causes the shaft to rotate at 1700 rpm . If the outer diameter of the shaft is 8 in. and the wall thickness is $\frac{3}{8}$ in.