-6b > 42 = b<-7
or
4b > -4 = b>-1
Hope this helps.
Answer: 153
Step-by-step explanation:
The maximum number of dots that can be seen from one position is 153 dots.
6:42 pm because you just subtract the elapsed time.
7978 years
Step-by-step explanation:
A = A02^(-t/hl)
where hl = half-life.
Dividing both sides by A0 and taking the logarithm, we get
ln(A/A0) = -(t/hl)ln2
or solving for t,
t= -(hl)ln(A/A0)/ln2
note that A/A0 = 0.38
t = -(5715 yrs)[ln(0.38)/ln2]
= 7978 years
