The volume of <span>a right square pyramid is

, where </span><span>

is basis area.
</span>
If the lengths of the sides of the base remain fixed and height
<span>is multiplied by a factor 10, than new height is

and the volume is
</span>
Your answer will be be because when you subtract 314 is one ask but instead of one actually just put one
Answer:
D. p + q = 7
Step-by-step explanation:
The slope of AB is ...
mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)
The slope of BC is ...
mBC = (q -1)/(9 -6) = (q -1)/3
We want the product of these slopes to be -1:
mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)
-(q-1)/(6 -p) = -1 . . . . cancel factors of 3
q -1 = 6 -p . . . . . multiply by -(6 -p)
q + p = 7 . . . . . matches choice D
Answer:
Step-by-step explanation:
The first two questions are answered here
<h3>Question 3</h3>
Use the equation for exterior angle
<u>Exterior angle = sum of non-adjacent interior angles</u>
- 5x - 2 = 2x + 76
- 5x - 2x = 76 + 2
- 3x = 78
- x = 26