Answer:
B. y=-4
Step-by-step explanation:
The horizontal asymptote is the horizontal line that the graph behaves as if it is going to touch as the x-values approaches positive and negative infinity.
From the graph the horizontal asymptote is
![y = - 4](https://tex.z-dn.net/?f=y%20%3D%20%20-%204)
As we move towards negative infinity the graph approaches y=-4.
As we move towards positive infinity the graph approaches y=-4.
The correct answer is option B.
HI + IJ = HJ
=> x + 12 + 16 + x = 20
<=> 2x + 28 = 20
<=> 2x = -8
<=> x = -4
with x = -4 => HI = - 4 + 12 = 8
Step-by-step explanation:
Answer:
21 minutes
Step-by-step explanation:
Given the following :
Taking CITY STREET:
Time taken to drive to nearest bowling alley = 45 minutes = 45/60 = 0.75 hours
Speed of travel = 30 miles per hour
Taking FREEWAY:
speed of travel = 65miles per hour
If the distance to bowling alley is the same along both routes, The time taken along FREEWAY will be :
.
Distance to bowling alley taking city center :
Speed = distance / time
30 mph = distance / 0.75 hour
Distance = 30 × 0. 75 = 22.5 miles
Since distance is the same :
Time taken along FREEWAY :
Time taken = distance / speed
Time taken = 22.5 / 65 = 0.3461538 hour
Converting to minutes :
0.3461538 × 60 = 20.769 minutes
= 21 minutes ( to the nearest minute)
The graph of a function must be linear if x is not squared in the function
Answer with explanation:
Given the function f from R to ![(0,\infty)](https://tex.z-dn.net/?f=%280%2C%5Cinfty%29)
f: ![R\rightarrow(0,\infty)](https://tex.z-dn.net/?f=R%5Crightarrow%280%2C%5Cinfty%29)
![-f(x)=x^2](https://tex.z-dn.net/?f=-f%28x%29%3Dx%5E2)
To prove that the function is objective from R to ![(0,\infty)](https://tex.z-dn.net/?f=%280%2C%5Cinfty%29)
Proof:
![f:(0,\infty )\rightarrow(0,\infty)](https://tex.z-dn.net/?f=f%3A%280%2C%5Cinfty%20%29%5Crightarrow%280%2C%5Cinfty%29)
When we prove the function is bijective then we proves that function is one-one and onto.
First we prove that function is one-one
Let ![f(x_1)=f(x_2)](https://tex.z-dn.net/?f=f%28x_1%29%3Df%28x_2%29)
![(x_1)^2=(x_2)^2](https://tex.z-dn.net/?f=%28x_1%29%5E2%3D%28x_2%29%5E2)
Cancel power on both side then we get
![x_1=x_2](https://tex.z-dn.net/?f=x_1%3Dx_2)
Hence, the function is one-one on domain [tex[(0,\infty)[/tex].
Now , we prove that function is onto function.
Let - f(x)=y
Then we get ![y=x^2](https://tex.z-dn.net/?f=y%3Dx%5E2)
![x=\sqrt y](https://tex.z-dn.net/?f=x%3D%5Csqrt%20y)
The value of y is taken from ![(0,\infty)](https://tex.z-dn.net/?f=%280%2C%5Cinfty%29)
Therefore, we can find pre image for every value of y.
Hence, the function is onto function on domain ![(0,\infty)](https://tex.z-dn.net/?f=%280%2C%5Cinfty%29)
Therefore, the given
is bijective function on
not on whole domain R .
Hence, proved.