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MaRussiya [10]
3 years ago
13

One pipe fills a storage pool in 8 hours. A second pipe fills the same pool in 4 hours. When a third pipe is added and all three

are used to fill the​ pool, it takes only 2 hours. Find how long it takes the third pipe to do the job
Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0
The first pipe fills 1/8 of a pool in one hr.
The second pipe fills 1/4 of a pool in one hr.

(1/8+1/4)2= 3/4 done by the first two pipes in 2 hours.
Therefore the last pipe must do 1 1/4 of the filling in 2 hours, which is 5/8 per hour.

5/8x=1
x=8/5

It takes the third pipe 1 hour and 36 minutes to fill it by itself.
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SOLUTION:

If it takes 5 sewing machines 5 minutes to make 5 shirts, then that means:

100 machines will make 100 shirts in 5 minutes as well.

Hope this helps! :)
Have a lovely day! <3
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What is the volume of a figure that is 5cm,5cm,8cm,8cm,8cm,1cm
Ratling [72]

Answer:

the volume is 40 cm

Step-by-step explanation:

to find the volume all you need is length times width times height and you multiply it and that is your answer

7 0
3 years ago
I am a 2 digit even mumber i am less than 60 add my digits to get 12 subtract one of my digits from the other to get 4 what mumb
True [87]

I THINK THE ANSWER IS 12

6 0
3 years ago
Calculate the value for each determinant:
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

\begin{vmatrix}3 & -1\\ -3 & 4\end{vmatrix}=(3\times 4)-(-1)\times (-3)

               = 12 - 3

               = 9

\begin{vmatrix}8 & -1\\ -4 & -1\end{vmatrix}=8\times(-1)-(-1)\times(-4)

               = -8 - 4

               = -12

\begin{vmatrix}-12 & -1\\ 12 & 5\end{vmatrix}=(-12)\times(5)-(-1)\times(12)

                = -60 + 12

                = -48

\begin{vmatrix}2 & -1\\ 2 & -1\end{vmatrix}=2\times(-1)-(2)\times(-1)

            = -2 + 2

            = 0

\begin{vmatrix}0 & -1\\ 17 & 4\end{vmatrix}=0\times(4)-(-1)\times(17)

              = 17

\begin{vmatrix}1 & 0\\ 0 & 1\end{vmatrix}=1\times(1)-(0)\times(0)

          = 1

6 0
2 years ago
Read 2 more answers
At which values of x does the graph of the function F(x) have a vertical asymptote? Check all that apply. f(x)=x+4/x^2+5x-24
mr Goodwill [35]

Answer:

x = -8   &   at x = 3

Step-by-step explanation:

This is a rational function.

We can get the values of x at which vertical asymptotes occur by setting the denominator equal to 0 and solving for x.

Let's do this:

x^2+5x-24=0\\(x+8)(x-3)=0\\x=-8,3

Hence, vertical asymptotes occur at x = -8 & at x = 3

3 0
3 years ago
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