Question

C6H12O6+6O2→6CO2+6H2O

Answer 1

Answer:

The answer that is true is A

Explanation:

The first thing to do is to perform stoichiometry relationships and calculations.

First relationship: 0.3 moles of CO₂ are produced

6 mol CO₂ _____ 1 mol C₆H₁₂O₆

0.3 mol CO₂ _____ X = 0.05 mol of C₆H₁₂O₆

Calculation: 0.3 mol x 1 mol / 6 mol = 0.05 mol of C₆H₁₂O₆

Second relationship: 0.60 moles of CO₂ are produced

6 mol CO₂ _____ 1 mol C₆H₁₂O₆

0.6 mol CO₂_____ X = 0.1 mol of C₆H₁₂O₆

Calculation: 0.6 mol x 1 mol / 6 mol = 0.1 mol of C₆H₁₂O₆

6 mol CO₂ _____ 6 mol O₂

0.6 mol CO₂ _____ X = 0.6 mol of O₂

Calculation: 0.6 mol x 6 mol / 6 mol = 0.6 mol of O₂

Then, the answer that is true is A, because in order for 0.6 moles of CO₂ to be produced, there must initially be 0.1 mol of C6H12O6 as calculated.

The B is not correct because for more CO₂ to be produced, more C₆H₁₂O₆ must react, this is defined according to Proust's law or law of defined proportions, stated as: “When the combination of two or more elements occurs to form a new compound, they always do it in a mass relationship that is completely constant”. It is by this law that no more CO₂ can be produced with the same amount of C₆H₁₂O₆ reagent.

The C is not correct either, although the temperature and volume of the container are the same, the O₂ is in excess to react, so 0.6 mol of it is needed to produce 0.6 mol of CO₂, according to the calculations made .

The D is not correct because it would also not respect the law of defined proportions or Proust's law. Although O₂ is in excess, it cannot react more than the stoichiometric ratio. Simply, if it is in excess, the rest of the O₂ will remain unreacted.