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s344n2d4d5 [400]
2 years ago
8

A sample of the mineral hematite Iron (III) oxide has a mass of 12.4g. How many moles of the mineral are present?

Chemistry
1 answer:
8090 [49]2 years ago
8 0

Thus problem is providing us with the mass of iron (III) oxide as 12.4 g so the moles are required and found to be 0.0776 mol after the calculations:

<h3>Mole-mass relationships:</h3>

In chemistry, we use mole-mass relationships in order to calculate grams from moles and vice versa. In this case, since we are given the mass of iron (III) oxide as 12.4 g one can calculate the moles by firstly quantifying its molar mass:

Fe_2O_3\rightarrow 2*55.85 g/mol+3*16.00 g/mol=159.7g/mol

Then, we prepare a conversion factor in order to cancel out the grams and thus, get moles:

12.4gFe_2O_3*\frac{1molFe_2O_3}{159.7gFe_2O_3} \\\\=0.0776molFe_2O_3

Learn more about mole-mass relationships: brainly.com/question/18311376

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Answer:

mass.

Explanation:

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If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?
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only 2.5 grams will be present after 16 years have passed

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3 years ago
Which way does current flow in a galvanic cell?
SCORPION-xisa [38]

In a galvanic cell, the flow of electrons will be from the anode to cathode through the circuit .

Whether a cell is an electrolysis cell (non-spontaneous chemistry driven by forcing electricity from an external energy source) or a galvanic cell (spontaneous chemistry driving electricity), will determine the charge of the anode and the cathode. Depending on where the electrons encounter resistance and find it difficult to pass, a negative charge may emerge. Therefore, you cannot determine the direction of the current just on the charge on the electrode.

Oxidation and reduction always take place at the anode and cathode, respectively.

An element undergoes oxidation when it surrenders one or more electrons to become more positively charged. These electrons leave the chemicals in any type of cell and travel to the anode, where they enter the external circuit.

An element picks up an electron during reduction to become more negatively charged (less positive, lower oxidation state). These electrons are captured from the external circuit at the cathode in both types of cells.

Therefore, no matter what kind of cell you are dealing with, the oxidizing chemicals at the anode transfer the electrons to the external circuit; these electrons then move through the circuit from the anode to the cathode, where they are captured by the reducing chemicals. The electrons always go from the anode to the cathode via the external circuit.

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7 0
1 year ago
A sample of 0.0860 g of sodium chloride is added to 30.0 mL of 0.050 M silver nitrate, resulting in the formation of a precipita
Grace [21]

Answer:

0.21 g

Explanation:

The equation of the reaction is;

NaCl(aq) + AgNO3(aq) -----> NaNO3(aq) + AgCl(s)

Number of moles of NaCl= 0.0860 g /58.5 g/mol = 0.00147 moles

Number of moles of AgNO3 = 30/1000 L × 0.050 M = 0.0015 moles

Since the reaction is 1:1, NaCl is the limiting reactant.

1 mole of NaCl yields 1 mole of AgCl

0.00147 moles of NaCl yields 0.00147 moles of AgCl

Mass of precipitate formed = 0.00147 moles of AgCl × 143.32 g/mol

= 0.21 g

3 0
2 years ago
I have seven energy levels, but only 1 valence eletron?
Olenka [21]

Answer:

Francium (Fr)

Explanation:

Looking at the periodic table, Francium has 7 energy levels as it is in the 7th Period and is in the 1st Group (meaning it has one electron in the outermost shell) which suggests that it has one valence electron.

<em>Hope this helps and be sure to have a wonderful time ahead at Brainly! :D</em>

3 0
2 years ago
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