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lesya [120]
3 years ago
7

Use the diagram to solve. What is 260% of 6

Mathematics
2 answers:
Serga [27]3 years ago
6 0

Answer:

15.6

Step-by-step explanation:

because 6×2.60

iragen [17]3 years ago
6 0

Answer:

15.60

Step-by-step explanation:

6 times 2 plus 60% of 6

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Which number is equivalent to 17.02?<br> 17.020 , 17.22 , 17 , 17.002
Irina18 [472]

Answer:

Step-by-step explanation:

17.020

3 0
3 years ago
5(p - 1) + 3(p - 0.75)<br> (Iready)
Kaylis [27]

Answer:

=8p−7.25

Step-by-step explanation:

=(5)(p)+(5)(−1)+(3)(p)+(3)(−0.75)

=5p+−5+3p+−2.25

=5p+−5+3p+−2.25

=(5p+3p)+(−5+−2.25)

=8p+−7.25

7 0
2 years ago
Read 2 more answers
Multiply and Simplify. 4x+4/x^2 × (x+2)(x-1)/x+1
NARA [144]

Answer:


Step-by-step explanation:

(x^2 - 4)(x^2 - 4)

Simplifying

(x2 + -4)(x2 + -4)

Reorder the terms:

(-4 + x2)(x2 + -4)

Reorder the terms:

(-4 + x2)(-4 + x2)

Multiply (-4 + x2) * (-4 + x2)

(-4(-4 + x2) + x2(-4 + x2))

((-4 * -4 + x2 * -4) + x2(-4 + x2))

((16 + -4x2) + x2(-4 + x2))

(16 + -4x2 + (-4 * x2 + x2 * x2))

(16 + -4x2 + (-4x2 + x4))

Combine like terms: -4x2 + -4x2 = -8x2

(16 + -8x2 + x4)

5 0
3 years ago
In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
damaskus [11]

Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

expected value= 1/38 * $315 + 37/38*(-$9) = $8.2894 - $8.7631

expected value= -$0.47368

You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

number of roll * expected value

1000 timer * -$0.47368/time= -$473.68

You are expected to lose $473.68 if you play the game 1000 times.

6 0
2 years ago
1489.45 Round this number to two decimal places​
Gekata [30.6K]
It is already rounded so you wont have to do anything.
8 0
3 years ago
Read 2 more answers
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