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3 years ago

Explain what happens to the pitch of a cell phone ringing when the amplitude of a sound wave increases.

Physics

2 answers:

lys-0071 [83]3 years ago

4 0

the pitch of the cell phone ringing will remains same when the amplitude of a sound wave increases.

The pitch of a sound wave depends on its frequency. more frequency means higher pitch and less frequency means lower pitch. The amplitude of wave is the maximum displacement of the particles of the medium from their mean positions. Increase in amplitude will increase the loudness and not the pitch. So the pitch remains same as the amplitude of sound wave is increased.

rewona [7]3 years ago

3 0

As the amplitude of a sound wave increases the pitch of the ringing would be much higher (like if you were to inhale helium.. just with a phone)

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the video identifies the force pair produced when an apple falls through the air. which force belongs in a free-body diagram of

trapecia [35]

The free-body diagram of an apple falling through the air has weight of the apple pointing downwards and the air-resistance on the apple acting upwards.

When an object falls from up to the ground, the object falls under in the influence of acceleration due to gravity.

The vertical component of the force on the apple as it falls trough the air is given as;

∑Fy = 0

Fₙ - W = 0

Fₙ = W

where;

<em>Fₙ is the frictional force on the apple acting upwards</em>
<em>W is the weight of the apple acting downwards</em>

The free-body diagram of the apple is represented as follows;

↑ Fₙ

↓ W

Thus, the free-body diagram of an apple falling through the air has weight of the apple pointing downwards and the air-resistance on the apple acting upwards.

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2 years ago

The more active a cell is, the more of these structures it has.

Aleks [24]

Answer:pretty sure its mitochondria

Explanation:

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4 years ago

At 2 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i

labwork [276]

Answer:

The distance between the ships changing at 6PM is 21.29Km/h

Explanation:

Ship A is sailing east at 35Km/h and ship B is sailing West at 25Km/h

Given

dx/dt= 35

dy/dt= 25

dv/dt= ???? at t= 6PM - 2PM= 4

Therefore t=4

We know ship A travels at 150km in the x-direction and Ship A at t=4 travels at 4.35 Which is 140 also in x-direction

So, we use:

$D^2 = (150 - x)^2 + y^2$ ;

$D^2 = (150 - 140)^2 + y^2$

But ship B travels at t=4, at 4.25 =100 in the y-direction

so, let's use the equation:

$D^2 = 10^2 + 100^2$

$= D= sqrt*(10 + 100)$

Lets use 2DD' = 2xx' + 2yy'

Differentiating with respect to t we have:

D•d(D)/dt = -(10)•dx/dt + 100•dy/dt

=100.5 d(D)/dt = (-10)•35 + (100)•25

When t=4, we have x=(140-150) =10 and y=100

$= D = sqrt*(10^2 + 100^2)$

=100.5

= 100.5 dD/dt = 10.35 +100.25

= dD/dt = 21.29km/h

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3 years ago

State the types of images that convex and concave mirrors create. Describe how each type of image is created.

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3 years ago

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A person walks at 2 metres per second for 8 seconds then at 1.5 metres per second for 8 seconds. What is the average speed

beks73 [17]

2 meters per second for 8 seconds

1.5 meters per second for 8 seconds

The average speed should be 1.8 or 1.7 but I think its 1.8

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3 years ago