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2 years ago

Explain what happens to the pitch of a cell phone ringing when the amplitude of a sound wave increases.

Physics

2 answers:

lys-0071 [83]2 years ago

4 0

the pitch of the cell phone ringing will remains same when the amplitude of a sound wave increases.

The pitch of a sound wave depends on its frequency. more frequency means higher pitch and less frequency means lower pitch. The amplitude of wave is the maximum displacement of the particles of the medium from their mean positions. Increase in amplitude will increase the loudness and not the pitch. So the pitch remains same as the amplitude of sound wave is increased.

rewona [7]2 years ago

3 0

As the amplitude of a sound wave increases the pitch of the ringing would be much higher (like if you were to inhale helium.. just with a phone)

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To model time-variant data, one must create a new entity in an m:n relationship with the original entity.

Ksenya-84 [330]

To model time-variant data, one must create a new entity in an m:n relationship with the original entity, is a False statement.

Like the majority of software engineering initiatives, the ER process begins with gathering user requirements. What information must be retained, what questions must be answered, and what business rules must be implemented (For instance, if the manager column in the DEPARTMENT table is the only column, we have simply committed to having one manager for each department.)

The end result of the E-R modeling procedure is an E-R diagram that can be roughly mechanically transformed into a set of tables. Tables will represent both entities and relationships; entity tables frequently have a single primary key, but the primary key for relationship tables nearly invariably involves numerous characteristics.

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10 months ago

A certain light truck can go around a flat curve having a radius of 150 m with a maximum spee dof 32.0 m/s. With what maximum sp

Dvinal [7]

Answer

Maximum speed at 75 m radius will be 22.625 m /sec

Explanation:

We have given radius of the curve r = 150 m

Maximum speed $v_{max}=32m/sec$

Coefficient of friction $\mu =\frac{v_{max}^2}{rg}=\frac{32^2}{150\times 9.8}=0.6965$

Now new radius r = 75 m

So maximum speed at new radius $v_{max}=\sqrt{\mu rg}=\sqrt{0.6965\times 75\times 9.8}=22.625m/sec$

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2 years ago

How long do molecules of groundwater stay in the ground?

Brilliant_brown [7]

CORRECT ANSWER:

d. Anywhere from days to thousands of years.

STEP-BY-STEP EXPLANATION:

The whole question from book is

How long do molecules of groundwater stay in the

ground?

a. Days

b. Weeks

c. Months

d. Anywhere from days to thousands of years

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3 years ago

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A cylinder of mass 250 kg and radius 2.60 m is rotating at 4.00 rad/s on a frictionless.

aleksandrvk [35]

Answer:

The angular momentum of a cylinder, when it is rotating with constant angular velocity is Lini =Iωi

. When two cylinders are added to the rotating cylinder, which are identical in their dimensions, the moment of inertia of the entire system increases (since mass increases). The final moment of inertia will be 3I

Since friction exist, all the cylinders start rotating with same angular velocity, the new angular velocity can be calculated using conservation of angular momentum

Thus, Iωi =3Iωf ⟹ωf =ωi/3 = 0.33ωi

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2 years ago

The direction equivalent to {40° W of S} is:

olchik [2.2K]

Answer:

Explanation:

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2 years ago