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blagie [28]
3 years ago
6

Explain what happens to the pitch of a cell phone ringing when the amplitude of a sound wave increases.

Physics
2 answers:
lys-0071 [83]3 years ago
4 0

the pitch of the cell phone ringing will remains same when the amplitude of a sound wave increases.

The pitch of a sound wave depends on its frequency. more frequency means higher pitch and less frequency means lower pitch. The amplitude of wave is the maximum displacement of the particles of the medium from their mean positions. Increase in amplitude will increase the loudness and not the pitch. So the pitch remains same as the amplitude of sound wave is increased.

rewona [7]3 years ago
3 0
As the amplitude of a sound wave increases the pitch of the ringing would be much higher (like if you were to inhale helium.. just with a phone)
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pashok25 [27]

Explanation:

It is given that, a robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns west for 2.0 meters.

Let east is +x, west is -x north is +y.

When it moves east for a distance of 5.0 meters, it means (5,0)

When it goes north for 3.0 meters, and then turns west for 2.0 meters, it means (0,3) +(-2,0)

(a) x-y coordinates for the resultant vector is (3,3)

(b) The magnitude of the resultant vector for the robot is given by :

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3 years ago
A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?
sp2606 [1]
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8 0
3 years ago
In the fusion reaction occurring in the Sun, how does the mass of helium atom formed compare to the mass of the hydrogen atoms?
PolarNik [594]
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3 0
3 years ago
A bicyclist is travelling at 25 m/s when he begins to decelerate at -4m/s2 . How fast is travelling after 5 seconds
Umnica [9.8K]

Initial velocity (Vi) = 25 m/s

acceleration (a) = -4 m/s^{2}

time interval (t) = 5 sec

let us assume that final velocity after 5 sec be Vf

As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e. V_{f} = V_{i} + at

Hence, V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s

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7 0
3 years ago
A woman living in a third-story apartment is moving out. Rather than carrying everything down the stairs, she decides to pack he
Flura [38]

Answer:

T = 480.2N

Explanation:

In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.

The forces on the boxes are:

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T: tension of the rope

M: mass of the boxes 0= 49kg

g: gravitational acceleration = 9.8m/s^2

The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.

By using the equation (1) you obtain:

T=Mg=(49kg)(9.8m/s^2)=480.2N

The woman needs to pull the rope at 480.2N

8 0
3 years ago
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