A rod of length L and electrical resistance R moves through a constant uniform magnetic field ; both the magnetic field and the
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Answer:
t_{out} = t_{in}, t_{out} =
Explanation:
This in a relative velocity exercise in one dimension,
let's start with the swimmer going downstream
its speed is
The subscripts are s for the swimmer, r for the river and g for the Earth
with the velocity constant we can use the relations of uniform motion
= D /
D = v_{sg1} t_{out}
now let's analyze when the swimmer turns around and returns to the starting point
= D /
D = v_{sg 2} t_{in}
with the distance is the same we can equalize
t_{out} = t_{in}
t_{out} = t_{in}
This must be the answer since the return time is known. If you want to delete this time
t_{in}= D /
we substitute
t_{out} = \frac{v_s - v_r}{v_s+v_r} ()
t_{out} =
Answer:
Momentum of block B after collision =
Explanation:
Given
Before collision:
Momentum of block A = =
Momentum of block B = =
After collision:
Momentum of block A = =
Applying law of conservation of momentum to find momentum of block B after collision .
Plugging in the given values and simplifying.
Adding 200 to both sides.
∴
Momentum of block B after collision =