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3 years ago

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Carbohydrates, fats, proteins: These organic molecules ALL have this element in common. This element can form multiple bonds, an

d it bonds with other elements as well as with itself. This element is

2 answers:

Tresset [83]3 years ago

8 0

Answer:

Carbon

Explanation:

Carbon is a component of all organic molecules such as proteins, fats, carbohydrates, etc.

<em>Carbon has the ability to form multiple bonds as a result of the presence of 4 valence electrons in its outer shell. It has the capacity to form C-C single, double or triple bonds and also forms bonds with other elements.</em>

statuscvo [17]3 years ago

6 0

Carbon is the answer. IF oxygen were on the list it would also be correct but for this its Carbon<span />

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A 25.0 kg bag of peat moss sits in the back of a flatbed truck, driving up a hill. The bag experiences a 225N normal force. The

malfutka [58]

Answer:

a

$\theta = 23.32^o$

b

$\mu_s = 0.27$

c

$s = 0.948 \ m$

Explanation:

From the question we are told that

The mass of the bag is $m_b = 25.0 \ kg$

The normal force experienced is $F_n = 225 \ N$

The maximum acceleration of the bag is $a = 2.40 \ m/s^2$

Generally this normal force experience by the bag is mathematically represented as

$F_n = mg cos \theta$

=> $225 = (25 * 9.8) cos \theta$

=> $0.9183 = cos \theta$

=> $\theta = cos^{-1}[0.9183]$

=> $\theta = 23.32^o$

Generally for the bag not to slip , it means that the frictional force is equal to the sliding force

$F_f = F_s$

Hence $F_f$ is mathematically represented as

$F_f = \mu_s * F_n$

While $F_s$ is mathematically represented as

$F_s = m * a$

So

$\mu_s * F_n = m * a$

=> $\mu_s * 225 = 25 * 2.40$

=> $\mu_s = 0.27$

Generally from the workdone equation we have that

$KE_f - KE_i = W_f$

Here $W_f$ is the work done by friction which is mathematically represented as

$W_f = m * g * \mu_k * s$

Here s is the distance covered by the bag

$KE_f$ is zero given that velocity at rest is zero

and

$KE_i = \frac{1}{2} * m* v_i^2$

so

$\frac{1}{2} * m* v_i^2 = m * g * \mu_k * s$

=> $\frac{1}{2} * v_i^2 = g * \mu_k * s$

substituting 2.55 m/s for v_i and 0.350 for \mu_k we have that

$\frac{1}{2} * 2.55^2 = 9.8 * 0.350 * s$

=> $s = 0.948 \ m$

4 0

3 years ago

A student throws a rock horizontally off a 5.0 m tall building. The rock's initial speed is 6.0 m/s. How long will it take the r

Archy [21]

Answer:

The time taken by the rock to reach the ground is 0.569 seconds.

Explanation:

Given that,

A student throws a rock horizontally off a 5.0 m tall building, s = 5 m

The initial speed of the rock, u = 6 m/s

We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :

$s=ut+\dfrac{1}{2}gt^2\\\\5=6t+\dfrac{1}{2}\times 9.8t^2\\\\t=0.569\ seconds$

So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.

5 0

3 years ago

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As a rocket travels upward from earth, air resistance decreases along with the force of gravity. The rocket's mass also decrease

ddd [48]

Answer:

The decrease of these factors increases the acceleration.

Explanation:

Hi, the decrease of these factors increases the acceleration.

Air resistance is a force opposing the acceleration. So if it decreases, the acceleration increases, because the opposite forces decreases.

The same is applied to the force of gravity, since the rocket travels upward; gravity is also an opposite force.

Finally, if the mass decreases, it means that the rocket becomes lighter and the force acting on the smaller mass causes an increase in the acceleration.

6 0

3 years ago

According to Newton’s second law of motion what is force equals to

Maksim231197 [3]

Answer:force equals to rate of change of momentum

Explanation:

F=force

t=time

m=mass

v=final velocity

u=initial velocity

(mv-mu)/t=rate of change of momentum

Force=rate of change of momentum

F=(mv-mu)/t

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3 years ago

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A 20.0-kg block is initially at rest on a horizontal surface. A horizontal force of 77.0 N is required to set the block in motio

saveliy_v [14]

Answer: The coefficient of static friction is 3.85 and The coefficient of kinetic friction is 2.8

Explanation:

in the attachment

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3 years ago