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BaLLatris [955]
3 years ago
7

At time t=3, there are 2.5 cubic feet of water in the tub. Write an equation for the locally linear approximation of W at t=3, a

nd use it to approximate the volume of water in the tub at time t=3.5
Mathematics
2 answers:
velikii [3]3 years ago
4 0

Answer:

W=0.8333*t

2.917 ft³

Step-by-step explanation:

At time t=3, there is 2.5 ft³ of water in the tub

Finding the relation will be;

3=2.5

1=?

Rate=0.8333 ft³/min

W=0.8333 ft³ / min

W=0.8333*t

At t=3.5 will be;

1 min = 0.8333

3.5 min =?

Apply cross-production

3.5*0.8333 =2.917 ft³

kotykmax [81]3 years ago
3 0

Answer:

<em>W= 2.952 cubic feet.</em>

Step-by-step explanation:

<em>From the equation given, we recall that,</em>

<em>At time t= 3, w= 2.5</em>

<em>Using Linear Approximation</em>

<em>(W - 2.5) = w¹ (3) { t -3}  - [ W¹ (3) = f (3) = tan⁻¹ (π)/2 - 3/10 = 0.904</em>

<em>W = 2.5 + 0.904 ( t -3)</em>

<em>W = 2.5 + 0.904t - 2.712</em>

<em>W = 0.904t - 0.212</em>

<em>at t = 3</em>

<em>W = 0.904 (3.5) - 0.212</em>

<em>W = 2.952 </em>

<em>Therefore the cubic feet is 2.952</em>

<em />

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