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3 years ago

Can somebody help me please!!!

Mathematics

1 answer:

Effectus [21]3 years ago

3 0

Answer:

Part A: 0

Part B: 0 or 1

Step-by-step explanation:

Part A: anything to the 0 power is 1 (x^0= x^y-y) if you solve 7^2 you get 49. 49^0= 1

Part B: Because it is already being raised to the power of 0, if x=0 it will remain equal to one (as explained above). Anything raised to the 1 power is itself, so 7^0= 1 and 1^1 =1

Hope this helped!

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