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zmey [24]
3 years ago
9

Geometry 2. Congruent triangles

Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0

Answer:

pq =28

Step-by-step explanation:

you set up the equation by making them equal each other 3x+4= 5x-12 and solve From there

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How can the following fraction 33/77 be in simplest form??
Dafna11 [192]
3/7 top and bottom are divisible by 12
8 0
3 years ago
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6 in.<br> 10 in.<br> 15 in.<br> V = [?] in.³<br> area of base<br> Volume of Prism B.h
Nadusha1986 [10]

Answer:

300

Step-by-step explanation:

A pyramid with a triangle-shaped base whose three triangular faces meet at the ap/ex. The triangular pyramid formula included both the volume and surface area of the pyramid. The triangular pyramid volume formula calculates the base area and the height whereas the surface area of the triangular pyramid calculates the base area, perimeter,, and slant height. Formulas for volume and surface area of the triangular pyramid are given below that are used in the triangular pyramid formula: 

Volume= 1/3 × Base area × Height

6 0
2 years ago
A pizza stand offer both hand- tossed and pan pizza. customer can add any combination of the six available topping.
photoshop1234 [79]
The correct choice would be 128.

If there are 6 options and the person can pick any number of toppings, we need to know the number of subsets that can be formed with 6. That would be 2^6 or 64.

Since there is a pan or hand-tossed option, we need to multiply 64 by 2 to find the total.
64 x 2 = 128
8 0
3 years ago
Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


5 0
3 years ago
Read 2 more answers
In cos(0.3), what unit would 0.3 be? Is it radians? Also if you were to solve it, would the answer be in radians as well? Please
neonofarm [45]

Answer:

22

Step-by-step explanation:

7 0
3 years ago
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