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arlik [135]
3 years ago
7

Contrast the chemical reactivity of potassium lithium and sodium

Chemistry
1 answer:
Colt1911 [192]3 years ago
4 0
Answer is: lithium is the least reactive and potassium is the most reactive of the three alkali elements. 
<span>The </span>reactivity<span> of the alkali metals increases down the group because one valence electron (I group of Periodic system of elements) is farther away from nucleus and attraction force between electron and proton is weaker.</span>
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Henry divides 1.060g by 1.0mlbto find the density of his water sample. How many significant figures should he include in the den
kykrilka [37]
<span>Henry divides 1.060 g by 1.0 mL to find the density of his water sample.
</span>He should include THREE significant figures in the density value that hereports.
3 0
3 years ago
How many grams would you have if you had 2.478 moles of Calcium Phosphate? (SHOW ALL WORK FOR BRAINLIEST)
saul85 [17]

Answer:u would have 40

Explanation:

because ur taking them away

5 0
3 years ago
How many atoms are in c6h4c12
Mekhanik [1.2K]

Answer:

their are a it is in the chemicle

Explanation:18 carbon and 4 hydrogen

so it is a toatle of 22 atoms

6 0
3 years ago
How many grams of HF are needed to react with 3.0 moles of Sn? *
Lostsunrise [7]

Answer:

120g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Sn + 2HF —> SnF2 + H2

Next, we shall determine the number of mole of HF needed to react with 3 moles of Sn.

From the balanced equation above, 1 mole of Sn reacted with 2 moles of HF.

Therefore, 3 moles of Sn will react with = 3 x 2 = 6 moles of HF.

Finally, we shall convert 6moles of HF to grams

This is illustrated below:

Number of mole of HF = 6moles

Molar Mass of HF = 1 + 19 = 20g/mol

Mass of HF =..?

Mass = number of mole x molar Mass

Mass of HF = 6 x 20

Mass of HF = 120g

Therefore, 120g of HF is needed to react with 3 moles of Sn

6 0
3 years ago
4 b + 3 o2 → 2 b2o3 if 8 moles of b and 4 moles of o2 are allowed to react, how many moles of b2o3 can be formed?
raketka [301]

The number of moles of  b2o3 that will be formed is determined as 4 moles.

<h3>Limiting reagent</h3>

The limiting reagent is the reactant that will be completely used up.

4 b + 3O₂ → 2b₂O₃

from the equation above;

4 b ------------> 2 b₂O₃

2b ------------> b₂O₃

2 : 1

3O₂  -------------> 2b₂O₃

3  :  2

b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;

4 b ------------> 2 moles of  b2o3

8 moles -------> ?

= (8 x 2)/4

= 4 moles

Thus, the number of moles of  b2o3 that will be formed is determined as 4 moles.

Learn more about limiting reactants here: brainly.com/question/14222359

#SPJ1      

6 0
2 years ago
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