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3 years ago

Contrast the chemical reactivity of potassium lithium and sodium

1 answer:

Colt1911 [192]3 years ago

4 0

Answer is: lithium is the least reactive and potassium is the most reactive of the three alkali elements.
<span>The </span>reactivity<span> of the alkali metals increases down the group because one valence electron (I group of Periodic system of elements) is farther away from nucleus and attraction force between electron and proton is weaker.</span>

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Match Term Definition

mart [117]

The correct answers are:

1. Lithium - C) Opaque solid with higher density

2. Lead - B) Malleable, soft, and shiny

3. Florine - D) Highly reactive gas

4. Krypton - A) Nonreactive gas

I hope that helps u!

7 0

2 years ago

Define ionization energy and explain why the second ionization energy of any element is higher than its first ionization energy.

pochemuha

The amount of energy required to remove the most loosely bound electron in1 mole of an atom in its neutral gaseous state. Atomic radius is smaller, great nuclear charge (pulling power of protons on less electrons)

7 0

2 years ago

Read 2 more answers

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$

$2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)$

Partial pressures at equilibrium:

$p^o_{H_2O}=0.070 atm$

$p^o_{H_2}=0.0035 atm$

$p^o_{O_2}=0.0025 atm$

The equilibrium constant in terms of pressures is given as:

$K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}$

$K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}$

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

5 0

2 years ago

The rate law for the reaction 3a ⟶⟶ c is rate = 4. 36 x 10–2 l • mol–1 • h–1[ a ]2 how long will it take in hours for the concen

Paha777 [63]

The hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

<h3>What is the rate law of a reaction?</h3>

Rate law depicts the rate of a chemical reaction depend on the concentration of the reactant.

The given reaction is second order reaction

Thus, the hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

Learn more about rate law of a reaction

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4 0

2 years ago

A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)â½ââây(g)+z(s) how are thes

Elan Coil [88]

The chemical equation given is:

<span>2x(g) ⇄ y(g)+z(s)</span>

Answer: the higher the amount of x(g) the more the forward reacton will occur and the higher the amounts of products y(g) and z(s) will be obtained at equilibrium.

Justification:

As Le Chatellier's priciple states, any change in a system in equilibrium will be compensated to restablish the equilibrium.

The higher the amount, and so the concentration, of X(g), the more the forward reaction will proceed to deal witht he high concentration of X(g), leading to an increase on the concentration of the products y(g) and z (s).

3 0

3 years ago