SOMEONE HELP PLS! I missed a day and I need help rn

Solutions of mercury (I) nitrate and potassium bromide are mixed

Afina-wow [57]

With that informatio you can:

1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.

I will do all four, for you:

1) Chemical equation:

mercury(I) nitrate potassium bromide mercury(I) bromide potassium nitrate
Hg2(NO3)2 + KBr → Hg2Br2 + KNO3

2) Balanced chemical equation

Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO3

3) Molar ratios or proportions:

1 mol Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO3

4) Prediction of precipitation.

You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.

7 0

2 years ago

The work function for metallic potassium is 2.3 eV. Calculate the velocity in km/s for electrons ejected from a metallic potassi

mote1985 [20]

Answer:

932.44 km/s

Explanation:

Given that:

The work function of the magnesium = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, work function = $2.3\times 1.6022\times 10^{-19}\ J=3.68506\times 10^{-19}\ J$

Using the equation for photoelectric effect as:

$E=\psi _0+\frac {1}{2}\times m\times v^2$

Also, $E=\frac {h\times c}{\lambda}$

Applying the equation as:

$\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

m is the mass of electron having value $9.11\times 10^{-31}\ kg$

$\lambda$ is the wavelength of the light being bombarded

$\psi _0=Work\ function$

v is the velocity of electron

Given, $\lambda=260\ nm=260\times 10^{-9}\ m$

Thus, applying values as:

$\frac{6.626\times 10^{-34}\times 3\times 10^8}{260\times 10^{-9}}=3.68506\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2$

$3.68506\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{260\times \:10^{-9}}$

$\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=7.64538\times 10^{-19}-3.68506\times 10^{-19}$

$\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=3.96032462\times 10^{-19}$

$v^2=0.869446\times 10^{12}$

v = 9.3244 × 10⁵ m/s

Also, 1 m = 0.001 km

So, v = 932.44 km/s

5 0

2 years ago

What is the mass in grams of 0.0015 mol of aspirin (C9H8O4)

almond37 [142]

Answer:

116.1 g

Explanation:

3 0

2 years ago

Read 2 more answers

Predidt the direction and the relative value of the dipole moment of the following bond: C-Cl

WINSTONCH [101]

Answer:

D. C → Cl electronegativity difference > 0.5

Explanation:

The electro negativity of an atom in a compound refers to its ability to attract the electrons of a bond towards itself.

On the Pauling's scale, carbon has an electro negativity value of 2.55 while that of chlorine is 3.16. The difference in electro negativity between the both atoms is about 0.61.

The dipole is aslways directed towards the more electronegative atom. Hence the direction is ; C → Cl

5 0

2 years ago

Which of the following is true about the principle of the conservation of mass? *

vova2212 [387]

Answer:

F

Explanation:

7 0

2 years ago