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2 years ago

Select the correct answer.

Chemistry

1 answer:

MakcuM [25]2 years ago

8 0

Answer:

Explanation:

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Refer to the Chemical Compounds table above. How many total elements are in<br> Ethanol?

Korolek [52]

Answer:

3 element i.e carbon (C), hydrogen (H) and oxygen.

Explanation:

The following data were obtained from the question:

Subtance >>>>>>>> Chemical Formula

Glucose >>>>>>>>> C₆H₁₂O₆

Methane >>>>>>>> CH₄

Ethanol >>>>>>>>> C₂H₅OH

Hydrogen peroxide >> H₂O₂

From the above table, we can see that ethanol (C₂H₅OH) contains carbon (C), hydrogen (H) and oxygen

Therefore, the total number of elements present in ethanol, C₂H₅OH is 3.

8 0

3 years ago

If you have 10cm of snow with a volume of 40mL and a density of 0.5 g/mL how many inches of rain is this?

Lelu [443]

Density is the mass of compound divided by its volume can be shown as follows:

$d = 0.5 g /mL = m /V = m /40 = 0.5$

$m = 20 g$

40 mL of snow having 20 g of mass calculated from density.

Now, 10 cm of snow = 3.93 inches = 20 g

As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.

10 inches rain = 11 inches snow

3.93 inches of snow produced by

$= (3.93 * 10) /11 = 3.57 inches rain.$

Thus, 3.57 incehs of rain produces by 10 cm snow.

4 0

2 years ago

Determine the mass of 4.25x10^26 formula units of barium hydroxide

Andru [333]

$4.25x10x^{26}$

5 0

2 years ago

Of the metal ions tested, sodium produces the brightest and most persistent color in the flame. Do you think potassium could be

elena55 [62]

Answer:

Yes, you can detect the difference visually.

7 0

2 years ago

A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As

TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

$P.V=n.R.T=\frac{m}{M} .R.T$

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

$m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g$

7 0

2 years ago