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jenyasd209 [6]
3 years ago
5

Write Qc for each of the following:(1) Gaseous sulfur tetrafluoride reacts with liquid water to produce gaseous sulfur dioxide a

nd hydrogen fluoride gas. (2) Solid molybdenum(VI) oxide reacts with gaseous xenon difluoride to form liquid molybdenum(VI) fluoride, xenon gas, and oxygen gas.
Chemistry
1 answer:
snow_tiger [21]3 years ago
7 0

Answer : The expression for reaction quotient will be :

(1) Q_c=\frac{[SO_2][HF]^4}{[SF_4]}

(2) Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}

Explanation :

Reaction quotient (Q_c) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

(1) The given balanced chemical reaction is,

SF_4(g)+2H_2O(l)\rightarrow SO_2(g)+4HF(g)

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.  So, the expression for reaction quotient will be :

Q_c=\frac{[SO_2][HF]^4}{[SF_4]}

(2) The given balanced chemical reaction is,

2MoO_2(s)+XeF_2(g)\rightarrow 2MoF(l)+Xe(g)+2O_2(g)[/texIn this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.  So, the expression for reaction quotient will be :[tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}

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A 10 gram sample of iron reacts with oxygen to form 18.2 grams of ferric oxide. How many grams of oxygen reacted?
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Answer:

\boxed {\boxed {\sf 8.2 \ grams}}

Explanation:

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In this problem, the reaction is:

iron + oxygen = ferric \ oxygen

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10 \ g + oxygen=18.2 \ g

We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.

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