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dybincka [34]
3 years ago
7

I need help? Please? ​

Chemistry
1 answer:
agasfer [191]3 years ago
3 0

Question: What is shown on the photo above?

Choices: A) An aquifer B) A sinkhole C) A watershed D) Karst topography

Answer: <u>It's C) A watershed because A. is where the water is underground, B. is a sinkhole and it has a big hole that is big or sometimes small, and D. Is where it has a little crack in it and it goes underground. </u>

<em>Hope this helps!.</em>

<em>~~~~~~~~~~~~~~~~~~~</em>

<em>~A.W~ZoomZoom44</em>

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How are elements in the same group in the periodic table alike
kolbaska11 [484]
C or D sorry if neither
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3 years ago
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3.5 grams is equivalent to how many kilograms? 3500 kg 35,000 kg 0.35 kg 0.0035 kg
bagirrra123 [75]
There are 1000 grams in a kg.
To convert g to kg, dovide by 1000.

3.5/1000= 0.0035 kg

Final answer: D
4 0
3 years ago
If an atom has the same equal amount of electron and proton is it charged or uncharged ​
Doss [256]

Answer:

Neutral or uncharged

Explanation:

The positive charge on a proton is equal in magnitude to the negative charge on an electron. As a result, a neutral atom must have an equal number of protons and electrons.

3 0
2 years ago
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The electron-domain geometry of a carbon-centered compound ch4 is tetrahedral. the hybridization of the central carbon atom is _
Nata [24]
The  hybridization  of  the   central  carbon  compound  CH4  tetrahedral  is
SP^3 hybridization 

In   tetrahedral  molecular  geometry    a central atom  is  located  at the  center  with  4  substituent  that  are located at  the  corners  of  tetrahedron. Example  in methane  molecules  is made  up of  b equally  spaced sp^3  hybrid  orbital  forming  bond  angle  of   109.5
5 0
3 years ago
A mixture containing 0.477 mol he(g), 0.265 mol ne(g), and 0.115 mol ar(g) is confined in a 7.00-l vessel at 25 ∘c. part a calcu
enot [183]
Q1)
we can use the ideal gas law equation to find the total pressure of the system ;
PV = nRT
where P - pressure
V - volume - 7 x 10⁻³ m³
n - number of moles 
total number of moles - 0.477 + 0.265 + 0.115 = 0.857 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in K - 273 + 25 °C = 298 K
substituting the values in the equation 
 P x 7 x 10⁻³ m³ = 0.857 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 303.33 kPa
1 atm = 101.325 kPa
Therefore total pressure - 303.33 kPa / 101.325 kPa/atm = 2.99 atm

Q2)
partial pressure is the pressure exerted by the individual gases in the mixture.
partial pressure for each gas can be calculated by multiplying the total pressure by mole fraction of the individual gas.

total number of moles - 0.477 + 0.265 + 0.115 = 0.857 mol
mole fraction of He - \frac{0.477}{0.857}  = 0.557
mole fraction of Ne - \frac{0.265}{0.857} =   0.309
mole fraction of Ar - \frac{0.115}{0.857}  = 0.134
partial pressure - total pressure x mole fraction
partial pressure of He - 2.99 atm x 0.557 = 1.67 atm
partial pressure of Ne - 2.99 atm x 0.309 = 0.924 atm
partial pressure of Ar - 2.99 atm x 0.134 = 0.401 atm
6 0
3 years ago
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