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3 years ago

I need help? Please?

Chemistry

1 answer:

agasfer [191]3 years ago

3 0

Question: What is shown on the photo above?

Choices: A) An aquifer B) A sinkhole C) A watershed D) Karst topography

Answer: It's C) A watershed because A. is where the water is underground, B. is a sinkhole and it has a big hole that is big or sometimes small, and D. Is where it has a little crack in it and it goes underground.

Hope this helps!.

~~~~~~~~~~~~~~~~~~~

~A.W~ZoomZoom44

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How does fermentation that causes dough to rise differ from fermentation in muscles?

mote1985 [20]

Fermentation that causes dough to rise is alcoholic acid, and this is when the alcohol is rising and leaving the dough. In a human, we don't have alcohol, or else we would be drunk after we work out. Instead, we have Lactic Acid fermentation, and this is when you use up too much oxygen, so fermentation make us really tired or else, we wouldn't be able to keep working out.

4 0

3 years ago

Read 2 more answers

A Question 2 (2 points) Retake question

Ksivusya [100]

Answer:

3.3765 Mol O2

Explanation:

There is no work for this problem

3 0

3 years ago

A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid

const2013 [10]

The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

Answer: The pH of the solution is 10.09

Explanation:

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HClO$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL$

Putting values in above equation, we get:

$1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL$

At equivalence, the number of moles of acid is equal to the number of moles of base. Also, the moles of salt which is NaClO will also be the same.

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For HClO:

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

$0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol$

For NaClO:

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

$\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M$

To calculate the pH of the solution, we use the equation:

$pH=7+\frac{1}{2}[pK_a+\log C]$

where,

$pK_a$ = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

$pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09$

Hence, the pH of the solution is 10.09

4 0

3 years ago

When heated, allyl aryl ethers and allyl vinyl ethers undergo a reaction called a Claisen rearrangement, a concerted reorganizat

Alex_Xolod [135]

Answer:

See explanation below

Explanation:

I found a picture of this exercise, to show you how to do this problem.

The first picture is the compound, and the second is the mechanism of reaction to do this claisen rearrangement.

Hope this helps

5 0

3 years ago

Identify the products formed in this Brønsted-Lowry reaction. HPO2−4+NO−2↽−−⇀acid+base

klemol [59]

Answer: The products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Explanation:

According to Bronsted-Lowry, acids are the species which donate hydrogen ions to another specie in a chemical reaction.

Bases are the species which accept a hydrogen ion upon chemical reaction.

For example, $HPO^{2-}_{4} + NO^{-}_{2} \rightleftharpoons HNO_{2} + PO^{2-}_{4}$

Here, the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Thus, we can conclude that the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

5 0

3 years ago

I need help? Please? ​

I need help? Please?