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Lena [83]
3 years ago
7

An aqueous solution is 26.0% by mass ammonia, nh3, and has a density of 0.904 g/ml. what is the molality of ammonia?

Chemistry
1 answer:
ivann1987 [24]3 years ago
6 0
V=1cm³

ms = 0,904g * 0,26 = 0,23504g
M=17,04g/mol

n = m / M = 0,23504g / 17,04g/mol ≈ 0,0138mol

mso = 0,904g - 0,23504g = 0,66896g

C = 0,0138mol / 0,66896g = 0,021 mol/0,001kg=21 mol/kg
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B) 0.32 %

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\begin{matrix}&CH_3COOH&\rightleftharpoons &CH_3COOH&+&H^+\\ At\ time, t = 0 &1.8&&0&&0\\At\ time, t=t_{eq}&-x&&+x&&+x\\ ----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:-&1.8-x&&x&&x\end{matrix}

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