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Lena [83]
3 years ago
7

An aqueous solution is 26.0% by mass ammonia, nh3, and has a density of 0.904 g/ml. what is the molality of ammonia?

Chemistry
1 answer:
ivann1987 [24]3 years ago
6 0
V=1cm³

ms = 0,904g * 0,26 = 0,23504g
M=17,04g/mol

n = m / M = 0,23504g / 17,04g/mol ≈ 0,0138mol

mso = 0,904g - 0,23504g = 0,66896g

C = 0,0138mol / 0,66896g = 0,021 mol/0,001kg=21 mol/kg
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Answer:

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In stoichiometric calculations, the amount of product formed from reactants can be determined.

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3 years ago
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Explanation:

Hello!

In this case, since the relationship between volume and pressure is inversely proportional, based on the Boyle's law:

P_1V_1=P_2V_2

Considering that the standard pressure is 101.325 kPa, we can compute the final pressure as shown below:

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2 years ago
Convert 1.25 atm to bar.
Tasya [4]

Answer: 1.27 bar

Explanation:

1 atm = 1.01325 bar

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1 atm•Z = 1.2665625 atm•bar

To get the value of Z, divide both sides by 1 atm

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Thus, 1.25 atm when coverted gives 1.27 bar

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