An aqueous solution is 26.0% by mass ammonia, nh3, and has a density of 0.904 g/ml. what is the molality of ammonia?

1 answer:

ivann1987 [24]3 years ago

6 0

V=1cm³

ms = 0,904g * 0,26 = 0,23504g
M=17,04g/mol

n = m / M = 0,23504g / 17,04g/mol ≈ 0,0138mol

mso = 0,904g - 0,23504g = 0,66896g

C = 0,0138mol / 0,66896g = 0,021 mol/0,001kg=21 mol/kg

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What is the percent ionization of a 1.8 M HC2H3O2 solution (Ka = 1.8 10-5 ) at 25°C?

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B) 0.32 %

Explanation:

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