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3 years ago

Please answer question now fast

Mathematics

1 answer:

german3 years ago

7 0

Answer:

its a

Step-by-step explanation:

on edge

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16. How many different words can be formed with the letters of the word 'RAJARAM'? In how many of

Mandarinka [93]

Answer:

The word "ARRANGE" can be arranged in

2!×2!

5040

=1260 ways.

For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.

Then the number of ways =

=360.

The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.

Also in the same way, the number of ways where two "A's" are together is 360.

The number of ways where two "A's" and two "R's" are together is 5!=120.

The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.

Step-by-step explanation:

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7 0

3 years ago

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In a group of 700 people only 5% of them have red hair how many people hade red hair

Svetradugi [14.3K]

35 people have red hair. Do 700 times 0.05.

3 0

3 years ago

Please help 30 points will give brainliest

Vinil7 [7]

Answer:

thats correct

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

laiz [17]

Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of $(h\circ g)(-6)$ is 2401.

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3 years ago

If the temperature in degrees Celsius , of a particular place from January to December was given as 9,11,12,12,13,14,14,14,16,15

Ira Lisetskai [31]

Answer:

use a calculator

Step-by-step explanation:

Add all of the numbers and divide by 12

5 0

3 years ago