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2 years ago

13

How do i solve -96=-6(1-3b) with the steps

1 answer:

Kay [80]2 years ago

5 0

Answer:

The answer is b= - 5

Step-by-step explanation:

-96 = -6 ( 1 - 3b )

-6 ( 1 - 3b ) = -96

$\frac{-6(1 - 3b}{-6} = \frac{-96}{-6}$

1 - 3b = 16

3b = 16 - 1 = 15

b= 15 : 3 = 5

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36, 27, <br> 81<br> 4<br> Find the 10th term.

zaharov [31]

a_{10} = \frac{177147}{65536} is solution of arithmetic progression (AP).

What is arithmetic progression (AP) in math?

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Write the general term through the pattern $a_{n} = 36( \frac{3}{4} )^{n-1}$

Substitute and calculate $a_{10} = \frac{177147}{65536}$

Learn more about arithmetic progression (AP)

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8 months ago

Karen is 6 years older than her sister Michelle, and Michelle is 2 years younger than their brother David. If the sum of their a

ale4655 [162]

$K\ \rightarrow\ the\ Karen's\ age\\M\ \rightarrow\ the\ Michelles\ age \\D\ \rightarrow\ the\ David's\ age\\\\K=M+6\\M=D-2\ \ \ \Rightarrow\ \ \ D=M+2\\K+M+D=62\\\\(M+6)+M+(M+2)=62\\3M+8=62\\3M=54\ /:3\\M=18\ \ \ \Rightarrow\ \ \ K=18+6=24\ \ \ and\ \ \ D=18+2=20\\\\Ans.\ Michelle\ is\ 18,\ David\ is\ 20,\ Karen\ is\ 24.$

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2 years ago

Are the following ordered pairs solutions to the equation 3x + 4y = 24 ? Select all true

wariber [46]

Answer:

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3 0

2 years ago

Read 2 more answers

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

2 years ago

Write a recursive rule for the sequence. Assume it starts with the 1st term. 10, 14, 18, 21...

Papessa [141]

Option D is correct. The correct option for the recursive formula is $f(0) =6;f(n)=f(n - 1)+4$

Given the sequence 10, 14, 18...

The first term is 10, hence

a1 = 10

The previous terms will be $a_{n-1}$

From the sequence, we can see that <em>4 is being added to the previous term to get the next term</em>. Hence the nth term will be expressed as:

$a_n = a_{n-1} + 4$

Get the term before the first term $a_0$

If n = 1

$a_1 = a_{1-1} + 4\\a_1 = a_{0} + 4\\a_0=a_1-4\\a_0=10-4\\a_0=6$

Hence the correct option for the recursive formula is $f(0) =6;f(n)=f(n - 1)+4$

Learn more here: brainly.com/question/18233843

3 0

2 years ago