All categories

4 years ago

What is the percent by mass of water in Na2SO4 • 10H2O?

1 answer:

3 0

M = M Na2SO4 + 10 M H2O
M = ((2 * 23 + 32 + 4 * 16) + 10 * 18) g/mole
M = (46 + 32 + 64 + 180) g/mole
M = 322 g/mole

So:
In 322 g Na2SO4 * 10H2O you have 180 g H2O
In 100 g Na2SO4 * 10H2O you have p g H2O

p is the mass percent of H2O in the Na2SO4 * 10H2O

p = (100 * 180)/322 = 55.90% H2O

You might be interested in

Please help it’s due really soon

shtirl [24]

The type of chemical bond depends on the substances taking part in it. If the substances are metal and non-metal, then the bond between them is ionic. If two substances are metal, then the bond between them is metallic. If two substances are non-metal, then the bond is covalent.

So basically put this:

Metal + Nonmetal = Ionic

Metal + Metal = Metallic

Nonmetal + Nonmetal = Covalent

8 0

2 years ago

Ammonium phosphate NH43PO4 is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric a

ira [324]

Answer:

0.767 moles of ammonium phosphate are produced

Explanation:

The reaction of ammona (NH3), with phosphoric acid is:

3 NH3 + H3PO4 → (NH4)3PO4

<em>Where 3 moles of ammonia reacts per mole of H3PO4 to produce 1 mole of ammonium phosphate.</em>

<em />

If 2.3 moles of ammonia reacts, the moles of ammonium phosphate produced if phosphoric acid is in excess are:

2.3 moles NH3 * (1 mole (NH4)3PO4 / 3 moles NH3) =

<h3>0.767 moles of ammonium phosphate are produced</h3>

<em />

5 0

3 years ago

How many atoms of phosphorus are in 7.00 mol of copper(II) phosphate?

Rama09 [41]

<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is $8.431\times 10^{24}$

<u>Explanation:</u>

We are given:

Moles of copper(II) phosphate $Cu_3(PO_4)_2$ = 7.00 mol

1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms

Moles of phosphorus in copper(II) phosphate = $(2\times 7.00mol$

According to the mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 7.00 moles of copper(II) phosphate will contain = $(2\times 7\times 6.022\times 10^{23}=8.431\times 10^{24}$ number of phosphorus atoms.

Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is $8.431\times 10^{24}$

3 0

3 years ago

Which chemical reaction shows photosynthesis?

Komok [63]

Answer:

Explanation:

Photosynthesis is reverse combustion, thus, water and carbon dioxide should be reactants. Photosynthesis also needs sunlight, so A it is.

6 0

3 years ago

26.5 g of a solution with a density of 7.48 g/mL

Cloud [144]

Answer: Assuming the question: 3.54 ml (3 sig figs)

Explanation:

I don't see a question, but will assume it is "What volume is needed to obtain 26.5 grams?

If so:

(26.5 g)/(7.48 ml) = 3.54 ml (3 sig figs)

6 0

3 years ago