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Monica [59]
3 years ago
6

? + HCl -> FeCl2 + ? CaO + ? -> Ca(NO3)2 + ? ? + Cu(OH)2 -> CuCl2 + ?

Chemistry
2 answers:
koban [17]3 years ago
7 0

Answer:

1. Fe / H2

2. HNO3 / H2O

3. HCI / H2O

Oksana_A [137]3 years ago
4 0

Answer:

1. Fe / H2

2. HNO3 / H2O

3. HCI / H2O

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(a) show that the pressure exerted by a fluid P (in pascals) is given by P= hdg, where h is the column of the fluid in metres, d
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Answer:

<em>56.4 m</em>

<em></em>

Explanation:

volume increases by factor of 6, i.e \frac{V2}{V1} = 6

Initial temperature T1 at bottom of lake =  5.24°C = 278.24 K

Final temperature T2 at top of lake = 18.73°C = 291.73 K

NB to change temperature from °C to K we add 273

Final pressure P2 at the top of the lake = 0.973 atm

Initial pressure P1 at bottom of lake = ?

Using the equation of an ideal gas

\frac{P1V1}{T1} = \frac{P2V2}{T2}

P1 = \frac{P2V2T1}{V1T2} = \frac{0.973*6*278.24}{291.73}

P1 = 5.57 atm

5.57 atm = 5.57 x 101325 = 564380.25 Pa

Density Ρ of lake = 1.02 g/cm^{3} = 1020 kg/m^{3}

acceleration due to gravity g = 9.81 m/s^{2}

Pressure at lake bottom = pgd

where d is the depth of the lake

564380.25 = 1020 x 9.81 x  d

d = \frac{564380.25}{10006.2} = <em>56.4 m</em>

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