Answer:
C. trophic levels
Explanation:
Trophic levels are the feeding positions of all organisms in a specific ecosystem. There are five main trophic levels, or feeding levels.
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Habitats are the environment in which organisms live. They are not feeding levels.
Taxonomic levels are a way of classifying species. They consist of (in order) domain, kingdom, phylum, class, order, family, genus, and species. They are not feeding levels.
Cladograms are branching diagrams that show the relationship between multiplt organisms/species. It too is not a feeding level.
Thus, is answer is C.
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Answer:
60%
Explanation:
Solute = the fruit juice = 75mL
Solution= solute + solvent = 75+50 = 125mL
% of solute = solute/ solution × 100 %
= 75/125 × 100 %
= 3/5 × 100 %
= 3 × 20 %
= 60%
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The correct unabbreviated electron configuration is as below
Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2
Strontium - 1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2
Carbon =1S2 2S2 2P2
<u><em> Explanation</em></u>
vanadium is in atomic number 23 in the periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2
Strontium is in atomic number 38 in periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4s2
Carbon is in atomic number 6 in periodic table therefore its electron configuration is 1s2 2s2 2p2
Answer:
The sample will be heated to 808.5 Kelvin
Explanation:
Step 1: Data given
Volume before heating = 2.00L
Temperature before heating = 35.0°C = 308 K
Volume after heating = 5.25 L
Pressure is constant
Step 2: Calculate temperature
V1 / T1 = V2 /T2
⇒ V1 = the initial volume = 2.00 L
⇒ T1 = the initial temperature = 308 K
⇒ V2 = the final volume = 5.25 L
⇒ T2 = The final temperature = TO BE DETERMINED
2.00L / 308.0 = 5.25L / T2
T2 = 5.25/(2.00/308.0)
T2 = 808.5 K
The sample will be heated to 808.5 Kelvin
