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scZoUnD [109]
4 years ago
15

In 2015 Michael purchased a stock for $45.80 a share. During the year he received $1.71 per share in cash dividends. At the end

of December of the same year, he sold the stock for $47.50 a share. What was Michael's TOTAL rate of return for his investment in this stock?
A.) 9.8%

B.) 7.7%

C.) 6.5%

D.) 8.8%
Mathematics
1 answer:
timama [110]4 years ago
7 0
Michael's initial investment is $45.80, the cost of the share. 
Michael Receives $1.71 in dividends.
He receives $47.50 for the stock when he sells it.
His profit on the sale of the stock is $47.50 - 45.80 = $1.70.
His total return on the stock is his total earnings, the dividends plus his profits on the sale of the stock, divided on what he paid initially, $45.80:
(1.71 + 1.70) ÷ 45.80 = .0744 = 7.45%
7.45% return on investment in less than a year, not bad!
Closest answer is 7.7%, not sure why it isn't exactly 7.45 or 7.5%. 

Answer is B) 7.7%
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3 years ago
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A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali
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Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

W = Wednesday

T = Thursday

F = Friday

S = Saturday

Their corresponding probabilities are

P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1

Since Y = number of days beyond Wednesday that it takes for both magazines to arrive(so possible Y values are 0, 1, 2 or 3)

The possible number of outcomes are therefore 4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)

The values associated for each of the outcomes are as follows:

Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3

The probability mass function of Y is,

P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19

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3 years ago
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Answer:

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3 years ago
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672,591 rounded to the nearest hundred thousand
vova2212 [387]
700,000

Look at the ten thousands place. There is a 7, which is greater than five, so that means you have to round the number 6 up to a seven
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I believe it would be 2:3. 

A 40:60 ratio could be simplified down to a 4:6 ratio which could then be simplified further to a 2:3 ratio. 
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