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Jobisdone [24]
2 years ago
11

Olly drove 56 km from Liverpool to Manchester.

Mathematics
1 answer:
yawa3891 [41]2 years ago
8 0

Answer:

57.073 km/h approx.

Step-by-step explanation:

Total distance from Liverpool to Sheffield

= 56 + 61 km

= 117 km

Time from Liverpool to Manchester

=56 km ÷ 70 km/h

=0.8 hours

Time from Manchester to Sheffield

=75 mins

=1.25 hours

Total time = 0.8 h + 1.25 h

= 2.05 hours

Average speed from Liverpool to Sheffield

= 117 ÷ 2.05

= 57.073 km /h

Please mark as brainliest

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2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diver
timofeeve [1]

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

y = 2x^{2} - 9x - 56

2x^{2} - 9x - 56 = 0

So

a = 2, b = -9, c = -56

Then

\bigtriangleup = b^{2} - 4ac = (-9)^{2} - 4*2(-56) = 529

x_{1} = \frac{-(-9) + \sqrt{529}}{2*2} = 8

x_{2} = \frac{-(-9) - \sqrt{529}}{2*2} = -3.5

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

7 0
3 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
2 years ago
For the graph x = 12 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your a
blagie [28]
Check the picture below.

that's the line of x = 12, just a straight vertical line, notice the green line, that's parallel to it, and the red line, that's perpendicular to it.

let's pick two points for each to get their slopes, hmm say for the green one (5,2) and (5,4)

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad 
(\stackrel{x_2}{5}~,~\stackrel{y_2}{4})
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-2}{5-5}\implies \stackrel{und efined}{\cfrac{2}{0}}

and for the red one hmmm (3,2) and (7,2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{2})\qquad 
(\stackrel{x_2}{7}~,~\stackrel{y_2}{2})
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-2}{7-3}\implies \cfrac{0}{4}\implies 0

8 0
3 years ago
Math<br><br><br> is my answer correct??<br><br><br> pls check!
Luba_88 [7]

Answer:

Domain: (-2 , 3]

Range: [-3, 2)

Step-by-step explanation:

Domain is all the x's on the graph. (If you have an equation, then it's all the numbers that are allowed to be x)

Range is all the y's on the graph (or if you have an equation, all the possible y outcomes)

Open dot endpoint means that point is not included in the set (domain and range are sets of numbers) Closed dot means the point is included.

You didn't get this math question right. But look for all the x's for the domain, and all the y's for the range.

6 0
2 years ago
Read 2 more answers
Why is triangle MNL and KNL the same?
irinina [24]
They are the same because both triangles have the same every to the other triangle.
5 0
2 years ago
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