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3 years ago

SO LOST! ASAP! Please show proof of your answer! I’m so lost...

Mathematics

2 answers:

polet [3.4K]3 years ago

8 0

Answer:

y = (x -3)² -2

Step-by-step explanation:

The vertex form of the equation of a parabola is ...

y = a(x -h)² + k

for vertex (h, k) and vertical scale factor "a".

Your graph shows the vertex to be at (x, y) = (3, -2). Note that one unit either side of the vertex, the graph goes up one unit. The number of vertical units difference from the vertex is the value of "a", so it is 1 for this parabola.

That means the equation is ...

y = 1·(x -3)² -2

or, more simply, ...

y = (x -3)² -2 . . . . . . . matches the 3rd choice

_____

Please note that if "a" is negative, the parabola will open downward. This one opens upward, so you can immediately reject the first two answer choices.

Luba_88 [7]3 years ago

4 0

Answer:c. Y=(x-3)^2-2

Step-by-step explanation: y=(x-3)^2-2

Y=x^2-6x+7

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MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

<u>Given functions</u>:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

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6 0

1 year ago

What is the volume, in cubic inches, of one cube with an edge length of 1/3 inch

DanielleElmas [232]

Answer:

1/27 cubic in.

Step-by-step explanation:

1/3*1/3*1/3= 1/27

3 0

2 years ago

Write an equation that represents the line.<br> Use exact numbers.

Greeley [361]

Answer:

Step-by-step explanation:

it is hard to know exactly by eye balling the graph I can't dissern the y intercept it might be 4.5 but it could be 4.33, but it looks for sure like the x intercept equals 6 but does it

the dots on the line are at (-2, -6) and (2, 3) so we can find the slope m

in the y = mx + b line equation b is the y intercept

m = Δy/Δx = (y1 - y2) / (x1 - x2)

= (-6 - -3) / (-2 - 2)

= -3 / -4

m = 3/4

y = 3x/4 + y intercept which i can't dissern (read directly from the

graph, but we believe y = 0 when x is six

0 = 3(6)/4 + y intercept

-18/4 = 18/4 -18/4 + y intercept

-9/2 = y intercept

-4.5 = y intercept

y = 3x/4 - 9/2 i think exact number means NO FRACTIONS but that is whole number so let me gaggle it What are exact numbers? Gaggle indicates exact numbers are integers example 3 ft in a yard 12 eggs in a dozen

y = 3x/4 - 9/2 multiple both sides by 4

4y = 3x - 36/2

4y = 3x - 18 <------------------ FINAL ANSWER

7 0

2 years ago

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

liberstina [14]

Correct answer is A.

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

<h3>How to calculate the diameter?</h3>

If you know the radius of the circle, multiply by 2 to get the diameter. The radius is the distance from the center of the circle to the edge. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2 = 8 cm. If you know the circumference of the circle, divide by π to get the diameter.

<h3>Briefing:</h3>

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction which is A.

The diameter of the circle is used for the square as l=2r therefore corresponds to the diameter, while for a hexagon r=r being the radius of the circle.

To know more about Diameter visit:

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I understand that the question you are looking for is:

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

A) The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

B) The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

C) The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

D) The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

7 0

1 year ago

I’m confused on how to answer this question

tester [92]

Answer:

i can do A for u

Step-by-step explanation:

the seed is one variable and the place where it was planted is another

8 0

2 years ago