<span>a. m∠L=58.1m∠L=58.1, m∠T=88.5m∠T=88.5, m∠D=33.4m∠D=33.4</span>
The second option i believe is correct
Answer:
Step-by-step explanation:
Represent the width by W. Then, "The length of a rectangular field is 7 m less than 4 times the width" expressed symbolically is
L = 4W - 7 (dimensions in meters)
Recall that the perimeter formula in this case is P = 2L + 2W, and recognize that the perimeter value is 136 m. After substituting 4W - 7 for L, we get:
136 m = 2(4W - 7) + 2W, or
136 = 8W - 14 + 2W, or
150 = 10W These three equations are equivalent mathematical statements.
150 = 10W reduces to W = 15 (meters).
Part A: the independent variable is W, the width of the field.
Part B: The mathematical statement is 136 m = 2(4W - 7) + 2W, which after algebraic manipulation becomes 150 = 10W.
Part C: The above equation can be solved for W: W = 15 meters. This is the value of the independent variable.
19-(-39)
19+39=58
is solution as
the two end points are 19 and -39 we should subtract then we get the distance between
81k^2 - m^2 factors to
(9k + m)(9k - m)
Prove this by FOILing.
First - 81k^2
Outer - (-9km)
Inner - 9km
Last - (-m^2)
Put it into equation form
81k^2 - 9km + 9km - m^2
And combine terms to get the original equation,
81k^2 - m^2.
⭐ Answered by Hyperrspace (Ace) ⭐
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