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erica [24]
3 years ago
6

What is the least common multiple of 15 and 8?

Mathematics
2 answers:
Sati [7]3 years ago
6 0
The LCM of 15 and 8 is 120
Arturiano [62]3 years ago
5 0
O get the Least Common Multiple (LCM) of 15 and 8 we need to factor each value first and then we choose all the factors which appear in any column and multiply them: 

<span><span>15:      35</span><span>8:   222  </span><span>LCM:   22235</span></span>

<span>The Least Common Multiple (LCM) is:   2 x 2 x 2 x 3 x 5 = 120</span>

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John wants to buy a skateboard that costs $150. The sales tax and 8.75%. What is the total cost of the equipment? $163.13 $153.1
kati45 [8]
Is any of the options that you put there.The correct answer would be $178.12
3 0
3 years ago
11. D'(2.9) is the image of D after a reflection
algol [13]

Answer:

D(- 2, 9 )

Step-by-step explanation:

Under a reflection in the y- axis

a pont (x, y ) → (- x, y )

Given D'(2, 9 ) is the image of D, then

D(- 2, 9 ) ← are the original coordinates

Since D(- 2, 9 ) → D'(2, 9 )

4 0
3 years ago
What is the total area of this composite figure rounded to the nearest hundredth?
Alex777 [14]

Answer:

39.53 ft^2

Step-by-step explanation:

We can find the area of the rectangle

A = l*w

   = 12*3 = 36

And the area of the semicircle

A = 1/2 pir^2

The diameter is 3, the radius is 3/2

   =1/2 pi* (3/2)^2

   = 1/2 *3.14 * 9/4

3.5325

Add the two areas together

36+3.532539.5325

Rounding to the nearest hundredth

39.53 ft^2

5 0
3 years ago
Consider the 1-to10^19 scale on which the disk of the Milky Way Galaxy fits on a football field. On this scale, how far is it fr
bezimeni [28]

Beautiful !  What a great exercise !  I won't even check to verify
that 1:10⁻¹⁹ is an appropriate scale to map the Milky Way onto a
football field.  I'll just accept it and go from there.

(4.4 light years) x (10⁻¹⁹) = (2.5848 x 10¹³ miles) x (10⁻¹⁹)

                                       =  2.5848 x 10⁻⁶ mile

                                       =    0.164 inch .

(1,391,400 kilometers) x (10⁻¹⁹) = 1.3914 x 10⁻¹⁰ meter


Research Conclusions:

If the Milky Way shrinks to fit on a football field, then

-- Alpha Centauri is  0.164 inch from us.

-- The sun's diameter is about 1.39 times that of a Hydrogen atom. 

Playing with this same fun concept a little more:

-- The Earth is sailing around in its orbit, once a year,
    about 0.000015 millimeter from the sun. 

-- It takes light almost 27 years to travel 1 inch !

wow  !
5 0
3 years ago
Read 2 more answers
Use quadratic regression to find the
Travka [436]

Answer:

y=  -x^{2} -2x+15

Step-by-step explanation:

 

y=  -x^{2} -2x+15

7 0
3 years ago
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