Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3)))) .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3))) ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3)) .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)
=2/sqrt(3) .... now rationalize
=2sqrt(3)/3
621,864
Since the 4 is a smaller digit than a 5, the 6 in the tens place would stay the same while the 4 would become a 0.
The value of this expression is 16. In exponential problems you can multiply the base by the number of times the exponent is. In this case it would be: 2*2*2*2. Then just multiply and get the product of 16.
Put the values of x to the equations of the functions:
1. f(9) → x = 9; f(x) = -3x + 10
f(9) = -3(9) + 10 = -27 + 10 = -17
2. f(-2) → x = -2; f(x) = 4x - 1
f(-2) = 4(-2) - 1 = -8 - 1 = -9
3. f(-5) → x = -5; f(x) = -2x + 8
f(-5) = -2(-5) + 8 = 10 + 8 = 18
3(5)+(-2+4(5))
15+(-2+20)
15+(18)
15+18
=33