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Ede4ka [16]
3 years ago
8

Evaluate the expression when x=5, y=4, z=3 z(y+x) please show work

Mathematics
2 answers:
fgiga [73]3 years ago
8 0
X=5, y=4, z=3 z(y+x) 
=> 3 ( 4 + 5 )
=> 3X4 + 3X5 
=> 12 + 15
=> 27...

Hope it helps !!!
ElenaW [278]3 years ago
4 0
3(4+5)
3*4 + 3*5
12+ 15 = 27
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Answer:

D; D

Step-by-step explanation:

The common difference of the first sequence is 10, so the coefficient is 10. The first term minus the common difference is -8, so that is the constant

The common difference of the second sequence is 3, so the coefficient is 3. The first term minus the common difference is -9, so that is the constant.

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2 years ago
Question 5
navik [9.2K]

Answer:

A. Similar using SAS; ∆ABC ~ ∆DFE

Step-by-step explanation:

m<B of ∆ABC = m<F of ∆DFE

AB corresponds to DF

AB/DF = 12/8 = 3/2

BC corresponds to FE

BC/FE = 24/16 = 3/2

Thus, the ratio of the corresponding sides of both triangles are the same. Therefore, both triangles has two sides that are proportional to each other, and also had an included corresponding angles that are congruent to each other.

By the SAS criterion, we can conclude that both triangles are similar to each other. That is, ∆ABC ~ ∆DFE

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2 years ago
Solve the equation below for x. <br> 500 = 25e ^ (2x)
Zigmanuir [339]

Answer:

x = i π n + log(20)/2 for n element Z

Step-by-step explanation:

Solve for x:

500 = 25 e^(2 x)

500 = 25 e^(2 x) is equivalent to 25 e^(2 x) = 500:

25 e^(2 x) = 500

Divide both sides by 25:

e^(2 x) = 20

Take the natural logarithm of both sides:

2 x = 2 i π n + log(20) for n element Z

Divide both sides by 2:

Answer: x = i π n + log(20)/2 for n element Z

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