3 years ago

Evaluate the expression when x=5, y=4, z=3 z(y+x) please show work

Mathematics

2 answers:

fgiga [73]3 years ago

8 0

X=5, y=4, z=3 z(y+x)
=> 3 ( 4 + 5 )
=> 3X4 + 3X5
=> 12 + 15
=> 27...

Hope it helps !!!

ElenaW [278]3 years ago

4 0

3(4+5)
3*4 + 3*5
12+ 15 = 27

You might be interested in

Three more than the quotient of a number and 4 is equal to 8

inn [45]

3+ x/4=8

................

..

6 0

3 years ago

Solve for x 3x-3>x+7

Sever21 [200]

Answer:

x>5

Step-by-step explanation:

6 0

3 years ago

7. Is the simplified form of 2 square root of 3 ⋅ 2 square root of 6 rational? (1 point)

Lynna [10]

Answer:

Yes

Step-by-step explanation:

I've done this before.

6 0

3 years ago

Select the basic integration formula you can use to find the indefinite integral.

kondaur [170]

Answer:

$\int \dfrac{du}{u}=\log|u|+C$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$

Step-by-step explanation:

$\int \dfrac{du}{u}=\log|u|+C$ $[\because \int \dfrac{dx}{x}=\log |x|+C]$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$ $[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$ $[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]$

3 0

3 years ago

What is the area of this shape?

stepan [7]

Answer:

10 I think

Step-by-step explanation:

well we add it all together 2+1+3+4

7 0

3 years ago

Read 2 more answers