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Ivan
3 years ago
7

1. Caches are important to providing a high-performance memory hierarchy to processors. Below is a list of 32-bit memory address

references, given as word addresses: 3, 180, 43, 2, 191, 88, 190, 14, 181, 44, 186, 253 [6 pts] a. For each of these references, identify the binary address, the tag, and the index given a directmapped cache with 16 one-word blocks. Also list if each reference is a hit or a miss, assuming the cache is initially empty. Show all your work.

Computers and Technology
1 answer:
inna [77]3 years ago
8 0

Answer:

It is paramount to notice that since we have word blocks and no address is separated then there are zero cache hits.Therefore the address sequence exhibits no temporal locality.

Check the attachment

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Answer:

import java.util.Scanner;

public class ANot {

   public static void main(String[] args) {

   Scanner input = new Scanner(System.in);

       System.out.println("Enter the month name:");

       String month1 = input.next();

       System.out.println("Enter the amount of rain for "+month1);

       double month1Rain = input.nextDouble();

       System.out.println("Enter the second month: ");

       String month2 = input.next();

       System.out.println("Enter the amount of rain for "+month2);

       double month2Rain = input.nextDouble();

       System.out.println("Enter the Third month: ");

       String month3 = input.next();

       System.out.println("Enter the amount of rain for "+month3);

       double month3Rain = input.nextDouble();

       double averageRainfall = (month1Rain+month2Rain+month3Rain)/3;

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   }

}

Explanation:

This is written in Java Programming language

  1. Import  the scanner class to prompt user for the inputs (Months and amount of rainfall for each month)
  2. Find the average of the three rainfall amount by adding up and dividing by 3
  3. Output the average. Pay particular attention to the use of java's printf in order to print the average to 2 decimal places
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Answer:

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