Question

Solve the following system of equations.

Answer 1

3y-2z=7

y=$\frac{2z+7}{3}$......equation(1)

Given x+2y-6=z

x=z-2y+6

putting value of y from equation(1)

By simplifying x=$\frac{-z+4}{3}$.....Equation(2)

Now putting the value of x and y in term of z in 3rd given equation

i.e 4+3x=2y-5z

i.e 2y-5z-3x=4

i.e 2($\frac{2z+7}{3}$)-5z-3($\frac{-z+4}{3}$)=4

By simplifying we will get -8z+14=24

i.e z=$\frac{-5}{4}$

Now putting z value in Equation(1);y=3/4

And putting z value in Equation(2);x=7/3 (Answer)