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svlad2 [7]
2 years ago
5

Integrate sin²2x cos²2x dx

Mathematics
1 answer:
DochEvi [55]2 years ago
7 0
\sin^2x=\dfrac{1-\cos2x}2
\cos^2x=\dfrac{1+\cos2x}2

From the identities above, you have

\sin^22x\cos^22x=\dfrac{(1-\cos4x)(1+\cos4x)}4=\dfrac{1-\cos^24x}4

Applying once more, you have

\dfrac{1-\cos^24x}4=\dfrac{1-\dfrac{1+\cos8x}2}4=\dfrac{1-\cos8x}8

So,

\displaystyle\int\sin^22x\cos^22x\,\mathrm dx=\frac18\int(1-\cos8x)\,\mathrm dx=\frac x8-\frac1{64}\sin8x+C
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Answer:

54m^2

Step-by-step explanation:

Each square has a equal sides, which is 3m

in order to find the surface area, it's

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3x3=9cm^2

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there are 6 squares so

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Data:

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mean is 96/6 = 16

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3 years ago
Pete and Teegan each put the same amount of money in a new bank account. Teegan's account earns 2.75% simple interest, and she e
ss7ja [257]

Answer:

$4

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Now, this $80 in Pete's account earns 5% simple interest.

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2 years ago
Find an ordered pair to represent a in the equation<br> a=2b+c if b=(6,3) and c=(-4,8)
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Answer:

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Step-by-step explanation:

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Replacing b and c in the equation above:

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