F(x)= 2x^2 + 3x <br> g(x) = x^2- x + 4

The lenght of a rope is 2.589 yards.round the lenght to the nearest tenth of a yard.

Sphinxa [80]

Please mark me brainiest i think the answer is 2.600

5 0

3 years ago

Compare the functions shown below:<br><br> Which function has the greatest maximum y-value?

solmaris [256]

Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3

The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.

For h(x), the max occurs when cosine is at its largest: when cos(x) = 1.
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well

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Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2

3 0

2 years ago

Read 2 more answers

How much is one can of peaches if the price for three is 2.99?

BabaBlast [244]

If the price for three of them is $2.99, then you divide that by three to find the price for one can. This would equal .9966666667, which could probably be rounded to 99 cents or just a dollar per can. Hope that helps.

7 0

3 years ago

En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,

Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0

3 years ago

How to do graphs of quadratic functions

Anastaziya [24]

Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2 y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

4 0

2 years ago

F(x)= 2x^2 + 3x g(x) = x^2- x + 4