Answer:
do u still need help it has been 2 weeks ??
Explanation:
Answer:
Okay!! What's the question?
Explanation:
Maybe I can help!
The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C
<h3>Coulomb's law equation </h3>
F = Kq₁q₂ / r²
Where
- F is the force of attraction
- K is the electrical constant
- q₁ and q₂ are two point charges
- r is the distance apart
<h3>How to determine the second charge </h3>
- Charge 1 (q₁) = –6×10¯⁶ C
- Electric constant (K) = 9×10⁹ Nm²/C²
- Distance apart (r) = 0.05 m
- Force (F) = 65 N
F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Divide both side by Kq₁
q₂ = Fr² / Kq₁
q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)
q₂ = +3.0×10¯⁶ C (since the force is attractive)
Learn more about Coulomb's law:
brainly.com/question/506926
Answer: 9 days
Explanation:
Let the rate of Leaf growth <em>r</em> be defined as,
= 
where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.
- Express the proportional relationship in equation.
Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.
r = kA, where k is the rate constant.
therefore, k = 
when A = 2
, A1 = 3
so k = 
=
÷ 2
= 0.33 ÷ 2
k = 0.167
- After calculating the rate constant k, we then find the time t when A1 is 5

- we have r = k × A1 =

so, 0.167 × 2 = 
0.33 =
.
t = 3/0.33
Therefore, t = 9 days.