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3 years ago

Why is the gravitational potential energy of an object 1 meter

Physics

1 answer:

amm18123 years ago

4 0

Answer:

This is because The object's acceleration due to gravity is less on the moon.

Explanation:

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qué le sucede a la intensidad de la luz de cada bombillo en un circuito en serie si agregas más bombillos al circuito?

aalyn [17]

La intensidad de la luz se baja con cada bombillo que agregas

7 0

3 years ago

A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration

Rufina [12.5K]

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

$F_f = \mu N$

Where,

$\mu =$ Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

$m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\$

By condition of Balance the friction force must be equal to the total net force, that is to say

$F_{net} = F_f$

$m_{total}a = \mu m_hg$

$(m_h+m_c)a = \mu*m_h*g$

Re-arrange to find acceleration,

$a= \frac{\mu*m_h*g}{(m_h+m_c)}$

$a = \frac{0.894*242*9.8}{(242+224)}$

$a = 4.54 m/s^2$

Therefore the acceleration the horse can give is $4.54m/s^2$

3 0

3 years ago

What is the difference between transverse and longitudinal waves? Transverse waves always have greater frequencies than do longi

Anastasy [175]

Answer:

Explanation:

6 0

3 years ago

What is the time period of a simple harmonic oscillator with a mass of 0.3kg and a force constant of 5N/m?

ikadub [295]

Answer: 6N/m

Explanation:

8 0

3 years ago

An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 581 km from the center of asteroid

mariarad [96]

Answer:

0.05806

Explanation:

$m_x$ = Mass of asteroid x

$m_y$ = Mass of asteroid y

$r_x$ = Distance from asteroid x = 140 km

$r_y$ = Distance from asteroid y = 581 km

m = Mass of asteroid

Force of gravity between asteroid x and the astronaut

$F_1=\frac{Gm_xm}{r_x^2}\\\Rightarrow F_1=\frac{Gm_xm}{140^2}$

Force of gravity between asteroid x and the astronaut

$F_2=\frac{Gm_ym}{r_y^2}\\\Rightarrow F_2=\frac{Gm_ym}{581^2}$

Here these two forces are equal as they are in equilibrium

$\frac{Gm_xm}{140^2}=\frac{Gm_ym}{581^2}\\\Rightarrow \frac{m_x}{140^2}=\frac{m_y}{581^2}\\\Rightarrow \frac{m_x}{m_y}=\frac{140^2}{581^2}\\\Rightarrow \frac{m_x}{m_y}=0.05806$

The ratio of the masses of the asteroid is 0.05806

4 0

3 years ago